Answer:
sulphuric acid as it is strong electrolyte and thus, ionises completely.
Explanation:
Answer: Option (A) is the correct answer.
Explanation:
Condensation is defined as the process in which vapors or gaseous phase changes into liquid phase.
Freezing is the process in which liquid phase changes into solid phase.
Evaporation is the process in which liquid phase changes into vapors or gaseous phase.
Melting is the process in which solid phase changes into liquid phase.
Therefore, we can conclude that names for given phase changes A and B is that A is condensation and B is freezing.
Answer:
Land resources such as gravel and bedrock are used to construct buildings, roads, and sidewalks. Land is also where city structures—such as buildings, roads, and sidewalks—are constructed. People use land resources such as bedrock and aggregate to construct buildings, roads, and sidewalks.
I hope this answer helps
<u>Answer:</u> The correct answer is Option b.
<u>Explanation:</u>
Reducing agents are defined as the agents which help the other substance to get reduced and itself gets oxidized. They undergo oxidation reaction.
![X\rightarrow X^{n+}+ne^-](https://tex.z-dn.net/?f=X%5Crightarrow%20X%5E%7Bn%2B%7D%2Bne%5E-)
For determination of reducing agents, we will look at the oxidation potentials of the substance. Oxidation potentials can be determined by reversing the standard reduction potentials.
For the given options:
- <u>Option a:</u>
![Ag^+](https://tex.z-dn.net/?f=Ag%5E%2B)
This ion cannot be further oxidized because +1 is the most stable oxidation state of silver.
- <u>Option b:</u>
![Pb](https://tex.z-dn.net/?f=Pb)
This metal can easily get oxidized to
ion and the standard oxidation potential for this is 0.13 V
![Pb\rightarrow Pb^{2+}+2e^-;E^o_{(Pb/Pb^{2+})}=+0.13V](https://tex.z-dn.net/?f=Pb%5Crightarrow%20Pb%5E%7B2%2B%7D%2B2e%5E-%3BE%5Eo_%7B%28Pb%2FPb%5E%7B2%2B%7D%29%7D%3D%2B0.13V)
- <u>Option c:</u>
![H_2](https://tex.z-dn.net/?f=H_2)
This metal can easily get oxidized to
ion and the standard oxidation potential for this is 0.0 V
![H_2\rightarrow 2H^++2e^-;E^o_{(H_2/H^{+})}=0.0V](https://tex.z-dn.net/?f=H_2%5Crightarrow%202H%5E%2B%2B2e%5E-%3BE%5Eo_%7B%28H_2%2FH%5E%7B%2B%7D%29%7D%3D0.0V)
- <u>Option d:</u>
![Ag](https://tex.z-dn.net/?f=Ag)
This metal can easily get oxidized to
ion and the standard oxidation potential for this is -0.80 V
![Ag\rightarrow Ag^{+}+e^-;E^o_{(Ag/Ag^{+})}=-0.80V](https://tex.z-dn.net/?f=Ag%5Crightarrow%20Ag%5E%7B%2B%7D%2Be%5E-%3BE%5Eo_%7B%28Ag%2FAg%5E%7B%2B%7D%29%7D%3D-0.80V)
- <u>Option e:</u>
![Mg^{2+}](https://tex.z-dn.net/?f=Mg%5E%7B2%2B%7D)
This ion cannot be further oxidized because +2 is the most stable oxidation state of magnesium.
By looking at the standard oxidation potential of the substances, the substance having highest positive
potential will always get oxidized and will undergo oxidation reaction. Thus, considered as strong reducing agent.
From the above values, the correct answer is Option b.
Answer:
number 7 or 3,5
Explanation:
sana po makatulong po sa inyo