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Answer:
Your answer would be a). 2.0 × 10-9
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Work:
In your question the "ph" of a 0.55 m aqueous solution of hypobromous acid temperature is at 25 degrees C, and it's "ph" is 4.48.
You would use the ph (4.48) to find the ka for "hbro"
[H+]
=
10^-4.48
=
3.31 x 10^-5 M
=
[BrO-]
or: [H+] = 10^-4.48 = 3.31 x 10^-5 M = [BrO-]
Then you would find ka:
(3.31 x 10^-5)^2/0.55 =2 x 10^-9
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<em>-Julie</em>
Answer:
The law of the conservation of mass states that matter is neither created nor destroyed, only converted to other forms. Therefore, the mass never changes, even if its appearance does.
Explanation:
Answer:
Ksp = 7.4x10⁻⁷
Explanation:
Molar solubility of a substance is defined as the amount of moles of that can be dissolved per liter of solution.
Ksp of Zn(OH)₂ is:
Zn(OH)₂(s) ⇄ Zn²⁺ + 2OH⁻
Ksp = [Zn²⁺] [OH⁻]²
And the molar solubility, X, is:
Zn(OH)₂(s) ⇄ Zn²⁺ + 2OH⁻
⇄ X + 2X
<em>Because X are moles of substance dissolved.</em>
<em>Ksp = </em>[X] [2X]²
Ksp = 4X³
As molar solubility, X, is 5.7x10⁻³mol/L:
Ksp = 4X³
Ksp = 4 (5.7x10⁻³mol/L)³
<h3>Ksp = 7.4x10⁻⁷</h3>
Answer:
a) Molarity = 0.199M
b) 21.6L of solution
c) 0.199 moles of sucrose in 1L
Explanation:
a) Molarity is the ratio of moles of solute (sucrose) in volume of solution (3.30L):
<em>Moles sucrose -Molar mass: 342,3g/mol-:</em>
225.0g * (1mol / 342,2965g) = 0.6573 moles
Molarity = 0.6573 moles / 3.30L
<h3>Molarity = 0.199M</h3><h3 />
b) 0.199M means 0.199 moles in 1L. 4.30 moles are in:
4.30 mol * (1L / 0.199mol) = 21.6L of solution
c) By definition, there are 0.199 moles of sucrose in 1L. This is the meaning of 0.199M
