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Brums [2.3K]
2 years ago
8

Can y’all please help me

Chemistry
1 answer:
lys-0071 [83]2 years ago
3 0

Answer The earth is not flat

Explanation:cuz

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The ph of a 0.55 m aqueous solution of hypobromous acid, hbro, at 25.0 °c is 4.48. what is the value of ka for hbro?
Alex Ar [27]

____________________________________________________

Answer:

Your answer would be a). 2.0 × 10-9

____________________________________________________

Work:

In your question the "ph" of a 0.55 m aqueous solution of hypobromous acid temperature is at 25 degrees C, and it's "ph" is 4.48.

You would use the ph (4.48) to find the ka for "hbro"

[H+]

=

10^-4.48

=

3.31 x 10^-5 M

=

[BrO-]

or: [H+] = 10^-4.48 = 3.31 x 10^-5 M = [BrO-]

Then you would find ka:

(3.31 x 10^-5)^2/0.55 =2 x 10^-9

____________________________________________________

<em>-Julie</em>

6 0
3 years ago
In , the bonds cause the carbon chain to bend or "kink", which gives the molecules an irregular shape. as a result, acids cannot
Anuta_ua [19.1K]

Answer:ur mom

Explanation:

8 0
3 years ago
What property of matter does not change even though the appearance may change?
IceJOKER [234]

Answer:

The law of the conservation of mass states that matter is neither created nor destroyed, only converted to other forms. Therefore, the mass never changes, even if its appearance does.

Explanation:

4 0
3 years ago
the molar solubility of Zn(OH)2 is 5.7x 10^-3 mol/L at a certain temperature. Calculate the value of Ksp for Zn(OH)2 at this tem
Alex

Answer:

Ksp = 7.4x10⁻⁷

Explanation:

Molar solubility of a substance is defined as the amount of moles of that can be dissolved per liter of solution.

Ksp of Zn(OH)₂ is:

Zn(OH)₂(s) ⇄ Zn²⁺ + 2OH⁻

Ksp = [Zn²⁺] [OH⁻]²

And the molar solubility, X, is:

Zn(OH)₂(s) ⇄ Zn²⁺ + 2OH⁻

                 ⇄ X + 2X

<em>Because X are moles of substance dissolved.</em>

<em>Ksp = </em>[X] [2X]²

Ksp = 4X³

As molar solubility, X, is 5.7x10⁻³mol/L:

Ksp = 4X³

Ksp = 4 (5.7x10⁻³mol/L)³

<h3>Ksp = 7.4x10⁻⁷</h3>

5 0
3 years ago
For an aqueous solution of sucrose (C12H22O11), determine: (a) the molarity of 3.30 L of a solution that contains 225.0 g of suc
dusya [7]

Answer:

a) Molarity = 0.199M

b) 21.6L of solution

c) 0.199 moles of sucrose in 1L

Explanation:

a) Molarity is the ratio of moles of solute (sucrose) in volume of solution (3.30L):

<em>Moles sucrose -Molar mass: 342,3g/mol-:</em>

225.0g * (1mol / 342,2965g) = 0.6573 moles

Molarity = 0.6573 moles / 3.30L

<h3>Molarity = 0.199M</h3><h3 />

b) 0.199M means 0.199 moles in 1L. 4.30 moles are in:

4.30 mol * (1L / 0.199mol) = 21.6L of solution

c) By definition, there are 0.199 moles of sucrose in 1L. This is the meaning of 0.199M

8 0
3 years ago
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