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Arturiano [62]
3 years ago
9

In the absence of sodium methoxide, the same alkyl bromide gives a different product. Draw an arrowpushing mechanism to account

for its formation. 6. (a) In the reaction in part 5(a), two additional products, which contain only carbon and hydrogen, are also formed. Draw their structures and propose mechanisms for their formation. Predict which of these two products would be formed in greater quantities. (b) In the reaction in part 5(b), two additional products, which contain only carbon

Chemistry
1 answer:
hoa [83]3 years ago
3 0

Answer:

See explanation below

Explanation:

The question is incomplete, cause you are not providing the structure. However, I found the question and it's attached in picture 1.

Now, according to this reaction and the product given, we can see that we have sustitution reaction. In the absence of sodium methoxide, the reaction it's no longer in basic medium, so the sustitution reaction that it's promoted here it's not an Sn2 reaction as part a), but instead a Sn1 reaction, and in this we can have the presence of carbocation. What happen here then?, well, the bromine leaves the molecule leaving a secondary carbocation there, but the neighbour carbon (The one in the cycle) has a more stable carbocation, so one atom of hydrogen from that carbon migrates to the carbon with the carbocation to stabilize that carbon, and the result is a tertiary carbocation. When this happens, the methanol can easily go there and form the product.

For question 6a, as it was stated before, the mechanism in that reaction is a Sn2, however, we can have conditions for an E2 reaction and form an alkene. This can be done, cause the extoxide can substract the atoms of hydrogens from either the carbon of the cycle or the terminal methyl of the molecule and will form two different products of elimination. The product formed in greater quantities will be the one where the negative charge is more stable, in this case, in the primary carbon of the methyl it's more stable there, so product 1 will be formed more (See picture 2)

For question 6b, same principle of 6a, when the hydrogen migrates to the 2nd carbocation to form a tertiary carbocation the methanol will promove an E1 reaction with the vecinal carbons and form two eliminations products. See picture 2 for mechanism of reaction.

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Darina [25.2K]

Answer:

Lithium's mass number would decrease by 1

Explanation:

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3 years ago
Water molecules that remain in a fixed position with very little motion would be characteristic of
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One gram of liquid benzene is burned in a bomb calorimeter. The temperature before ignition was 20.826 C, and the temperature af
Licemer1 [7]

Answer:

fH = - 3,255.7 kJ/mol

Explanation:

Because the bomb calorimeter is adiabatic (q =0), there'is no heat inside or outside it, so the heat flow from the combustion plus the heat flow of the system (bomb, water, and the contents) must be 0.

Qsystem + Qcombustion = 0

Qsystem = heat capacity*ΔT

10000*(25.000 - 20.826) + Qc = 0

Qcombustion = - 41,740 J = - 41.74 kJ

So, the enthaply of formation of benzene (fH) at 298.15 K (25.000 ºC) is the heat of the combustion, divided by the number of moles of it. The molar mass od benzene is: 6x12 g/mol of C + 6x1 g/mol of H = 78 g/mol, and:

n = mass/molar mass = 1/ 78

n = 0.01282 mol

fH = -41.74/0.01282

fH = - 3,255.7 kJ/mol

4 0
4 years ago
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Mrac [35]
The answer is 110., but round accordingly
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2 years ago
Define acid and base according to lewis theory, arrhenius theory and lawn theory
WITCHER [35]

Answer:

Three principal theories about acid-base are,

1. Arrhenius theory

2. Bronsted-Lowry theory

3. Lux-Flood definition

4. Lewis theory

5. Usanovich definition

1. According to the Arrhenius, acids give up hydrogen ion in aqueous medium and a base give up hydroxyl ion in its aqueous medium. Examples are aqueous solution of HCl, CH3COOH, PhCOOH, and H2SO4. These give up H+ in an aqueous medium. Aqueous solutions of NaOH, Ca (OH)2 are Arrhenius bases.

Arrhenius theory has some limitations. This theory cannot explain the acidic nature of BF3 or basic behavior of NH3. This theory fails to give any explanation about acidity and basicity which does not produce H+ and OH- in their aqueous solutions.

2. According to the Bronsted-Lowry, an acid releases proton and a base accepts proton. NH3 accepts proton and forms ammonium ion, so ammonia acts as a base.

But this theory also has limitations. According to this theory acidic behavior of BF3 still cannot be explained.

3. Lux-Flood describes the acid-base theories based on oxide ion transformation. It gives clear explanation for acid-bases theories of non-protonic system. According to them, a base will donate the oxygen atom and an acid will accept oxygen atom.

4. According to the Lewis theory, acids are those substances which accept electron pair and base are those substances which donates electron pairs. Lewis theory can explain the acidic nature of BF3. In BF3, B is two electrons short to fulfil its octet. So it can accept a pair of electrons from an electron donating substituent. So it is an electron pair acceptor compound and acts as an acid.

Substances which have π electrons can donate electron pair to an electron deficient substance and acts as a base. Ethylene and acetylene is Lewis bases. AlCl3, PCl3 are Lewis acids.

5. According Usanovich, an acid is some chemical species which would react with bases and yields cations or accepts anions or electrons. A base is some chemical species which would react with acids, yield anions or electrons or combine with cations.

Explanation:

8 0
2 years ago
Read 2 more answers
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