1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Arturiano [62]
3 years ago
9

In the absence of sodium methoxide, the same alkyl bromide gives a different product. Draw an arrowpushing mechanism to account

for its formation. 6. (a) In the reaction in part 5(a), two additional products, which contain only carbon and hydrogen, are also formed. Draw their structures and propose mechanisms for their formation. Predict which of these two products would be formed in greater quantities. (b) In the reaction in part 5(b), two additional products, which contain only carbon

Chemistry
1 answer:
hoa [83]3 years ago
3 0

Answer:

See explanation below

Explanation:

The question is incomplete, cause you are not providing the structure. However, I found the question and it's attached in picture 1.

Now, according to this reaction and the product given, we can see that we have sustitution reaction. In the absence of sodium methoxide, the reaction it's no longer in basic medium, so the sustitution reaction that it's promoted here it's not an Sn2 reaction as part a), but instead a Sn1 reaction, and in this we can have the presence of carbocation. What happen here then?, well, the bromine leaves the molecule leaving a secondary carbocation there, but the neighbour carbon (The one in the cycle) has a more stable carbocation, so one atom of hydrogen from that carbon migrates to the carbon with the carbocation to stabilize that carbon, and the result is a tertiary carbocation. When this happens, the methanol can easily go there and form the product.

For question 6a, as it was stated before, the mechanism in that reaction is a Sn2, however, we can have conditions for an E2 reaction and form an alkene. This can be done, cause the extoxide can substract the atoms of hydrogens from either the carbon of the cycle or the terminal methyl of the molecule and will form two different products of elimination. The product formed in greater quantities will be the one where the negative charge is more stable, in this case, in the primary carbon of the methyl it's more stable there, so product 1 will be formed more (See picture 2)

For question 6b, same principle of 6a, when the hydrogen migrates to the 2nd carbocation to form a tertiary carbocation the methanol will promove an E1 reaction with the vecinal carbons and form two eliminations products. See picture 2 for mechanism of reaction.

You might be interested in
Silver sulfate dissociates into silver ions and sulfate ions:
bagirrra123 [75]

Answer:

A its a step by step equation the answer is A

7 0
2 years ago
What force causes water to run down a mountain ?
miskamm [114]
What force causes water to run down a mountain
5 0
3 years ago
Angry pomeranian x bones? broken\broccoli boy anyone?
mezya [45]
Makes zero sense. What’s the question?
7 0
3 years ago
Please help. Im not a very smart person
GenaCL600 [577]
Either it’s, it is released when the reaction is complete or it is changed into atoms of carbon and oxygen during the reaction
7 0
2 years ago
An airplane travels 2100 km at 1000km/hE. It encounters a wind and slows to 800 km/h E for the next 1300 km. What is the average
Deffense [45]

Answer:

The average velocity of the airplane for this trip is 1684.21 km/h

Explanation:

Average velocity is the rate of change of displacement with time. That is,

Average velocity = \frac{Displacement }{Change in time} = Δx / Δt = \frac{x2 - x1}{t2 - t1}

Now we will calculate the time taken by the airplane for the first motion before it encounters a wind.

From,

Velocity = \frac{Distance traveled}{Time taken}

Time = \frac{Distance traveled}{Velocity}

Therefore, Time = \frac{2100km }{1000km/h}

Time = 2.1h

This is the time taken before the airplane encounters a wind.

Hence, t1 = 2.1h

Now, For the time taken by the airplane when it encounters a wind

Also from,

Velocity = \frac{Distance traveled}{Time taken}

Time = \frac{Distance traveled}{Velocity}

Therefore, Time = \frac{1300km }{800km/h}

Time = 1.625h

Hence, t2 = 1.625h

Now, to calculate the average velocity

Average velocity = \frac{x2 - x1}{t2 - t1}

x1= 2100, x2= 1300, t1= 2.1h and t2= 1.625h

Hence, Average velocity = \frac{1300 - 2100}{1.625 - 2.1}

Average velocity = 1684.21 km/h

7 0
2 years ago
Other questions:
  • Which best explains why sawdust burns more quickly than a block of wood of equal mass under the same conditions?
    6·2 answers
  • As a bond between a hydrogen atom and a sulfur atom is formed, electrons are(1) shared to form an ionic bond(2) shared to form a
    9·1 answer
  • A solution is prepared by mixing equal volumes of 0.16 M HCl and 0.52 M HNO3. (Assume that volumes are additive.)
    15·1 answer
  • Transition elements
    7·2 answers
  • The percentage by mass of Br in the compound
    5·2 answers
  • State the rank in the Brainly apk​
    7·1 answer
  • What is the molarity of 2.5 mol of H2SO4 dissolved in 1.00 L of solution? <br> Need FAST!
    5·1 answer
  • How many Liters of I2 are produced when 241.6 grams of KI are reacted with excess CuBr2?
    11·1 answer
  • How many lone pairs are on the central atom in GeH4?
    12·1 answer
  • Please help???? i dont know this
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!