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Marina CMI [18]
3 years ago
12

What is the difference between a physical and chemical change? From what I know a chemical change modifies the atoms of an objec

t while a physical change modifies the molecules right?
Chemistry
1 answer:
blsea [12.9K]3 years ago
6 0
Physical change: a change in which no new substances are formed. the form of the substance is changed but not it's chemical composition (ice melting, bread toasting)

chemical change: any change that results in the formation of new chemical substances. this type of change modifies molecules and atoms by making and breaking the bonds between atoms! (iron rusting, gas burning)

so basically a physical change just changes the appearance of a substance, but a chemical change changes the makeup on a molecular level. i hope this helps you out!
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Star A has a magnitude of 2. Star B has a magnitude of 5. What is the brightness ratio? A.6.3 : 1 B.15.8 : 1 C.5 : 2 D.2 : 5
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I think the answer is C
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How many moles are in 7950 g of CO2? ( pleas show calculation)
Mkey [24]

Answer:

Calculate the number of moles of CO2 by the formula n=PV/RT, where P is the pressure from Step 3, V is the volume from Step 2, T is the temperature from Step 1 and R is a proportionality constant equal to 0.0821 L atm / K mol.

Explanation:

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What does the chemical formula CaCI2 show about the compound or represents?
atroni [7]

Answer:

Two elements because Can is one element and Cl is another. The two is a coeficient that states how many of that element there is.

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How are carbon-based molecules suited for sustaining life?
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8 0
3 years ago
In a hospital laboratory, a 10.0 mL sample of gastric juice (predominantly HCl), obtained several hours after a meal, was titrat
LiRa [457]

Answer: 1.14

Explanation:

HCl+NaOH\rightarrow NaCl+H_2O

To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?\\V_1=10.0mL\\n_2=1\\M_2=0.1M\\V_2=7.2mL

Putting values in above equation, we get:

1\times M_1\times 10.0=1\times 0.1\times 7.2\\\\M_1=0.072M

To calculate pH of gastric juice:

molarity of H^+ = 0.072

pH=-log[H^+]

pH=-log(0.072)=1.14

Thus the pH of the gastric juice is 1.14

3 0
3 years ago
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