A 42-kg crate rests on a horizontal floor, and a 52-kg person is standing on the crate. (a) determine the magnitude of the norma
l force that the floor exerts on the crate. (b) Determine the magnitude of the normal force that the crate exerts on the person.
1 answer:
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Answer:
0.113097335529 Nm
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
a = Acceleration
I = Moment of inertia = 0.3 kgm²
Torque is given by
The magnitude of torque is 0.113097335529 Nm
Answer:
Explanation:
From the exercise we have:
To find the velocity after 2.4s we need to use the following formula:
The negative sign means that the kit is going down.