Friction occurs when the surfaces and heat of two surfaces grind against each other.
I think these are the answers
Answer:
d
Explanation:
we need the tea to be at first moist in order to get much more flavor. then supersaturated so that it increases the concentration of the flavor by it not being too sweet nor too salty. so just right.
Answer:
The correct answer will be "
". The further explanation is given below.
Explanation:
The potential energy will be,
⇒ 
The expression of force will be,
⇒ 
⇒ 
⇒ 
Force seems to be appealing because the expression has been negative. It therefore means that the force or substance is acting laterally in on itself.
Answer:
453 gm
Explanation:
<u>Immersed </u>objects are buoyed up by force equal to mass of displaced liquid
400 + 53 = 453 gm in air
To solve this problem we will apply the concepts related to Newton's second law that relates force as the product between acceleration and mass. From there, we will get the acceleration. Finally, through the cinematic equations of motion we will find the time required by the object.
If the Force (F) is 42N on an object of mass (m) of 83000kg we have that the acceleration would be by Newton's second law.

Replacing,


The total speed change
we have that the value is 0.71m/s
If we know that acceleration is the change of speed in a fraction of time,

We have that,


Therefore the Rocket should be fired around to 1403.16s