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tamaranim1 [39]
4 years ago
9

If 0.5 gramd of hcl is dissolved in 500 ml of solution what is the ph

Chemistry
1 answer:
Kisachek [45]4 years ago
8 0
Salts are composed of positive and negative ions packed closely together in a crystal lattice. The crystal is held together by the ionic forces among oppositely charged particles in the solid. When a crystal of a salt is placed in water, the polar water molecules arrange their dipoles around the ions of the crystal in such a way as to attract the ions. For example, a positive ion at a corner of the crystal will be surrounded by a group of water molecules aiming the negative end of their dipoles at the positive ion. If the forces of attraction of the water molecules for the positive ion are larger than the ionic forces holding the ion in the crystal, then the ion will leave the crystal and enter solution. See Figure 15.2
8. Carbon dioxide is somewhat soluble in water, especially if pressurized (otherwise, the soda you may be drinking while studying Chemistry would be “flat”). Carbon dioxide’s solubility in water is approximately 1.5 g/L at 25°C under a pressure of approximately 1 atm. Although the carbon dioxide molecule overall is non-polar, that is because the two individual C–O bond dipoles cancel each other due to the linearity of the molecule. However these bond dipoles are able to interact with water, making CO2 more soluble in water than non-polar molecules such as O2 or N2 that do not possess individual bond dipoles.
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The fraction of a radioactive isotope remaining at time t is (1/2)^t/t1/2 where t1/2 is the half-life. If the half-life of carbo
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Answer:

a) 1.065\times 10^{-8}fraction of carbon−14 in a piece of charcoal remains after 14.0 years.

b) 0.000\times 10^{-3}fraction of carbon−14 in a piece of charcoal remains after  1.900\times 10^4 years

c) 0.0000\times 10^{-4}fraction of carbon−14 in a piece of charcoal remains after  1.0000\times 10^5 years.

Explanation:

The fraction of a radioactive isotope remaining at time t is given by:

[A]=\frac{(\frac{1}{2})^t}{t_{\frac{1}{2}}}

Taking log both sides:

\log [A]=t\log[\frac{1}{2}]-\log [t_{\frac{1}{2}}]

[A] =  fraction at given time t

t_{\frac{1}{2}} = half life of the carbon−14 =5,730 years

a)When , t = 14 years

\log [A]=t\log[\frac{1}{2}]-\log [t_{\frac{1}{2}}]

\log [A]= 14 years\times (-3010)-\log [5,730 years]

[A]=1.065\times 10^{-8}

b)When , t = 1.900\times 10^4 years

\log [A]=t\log[\frac{1}{2}]-\log [t_{\frac{1}{2}}]

\log [A]= 1.900\times 10^4 years\times (-3010)-\log [5,730 years]

[A]=0.000\times 10^{-3} [/tex

c)When , t = 1.0000\times 10^5 years

\log [A]=t\log[\frac{1}{2}]-\log [t_{\frac{1}{2}}]

\log [A]= 1.0000\times 10^5 years\times (-3010)-\log [5,730 years]

[A]=0.0000\times 10^{-4}

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