Answer:
in acetic acid ,there are 4 hydrogen atoms
Explanation:
C H 3 C O O H
Answer:
Explanation:
Molar mass of sodium hydroxide is = 100
any compund with its molar mass dissovled in 1L itres solution gives rise to 1M solution
40 g ------> 1L ---->1M
Xg ------>1L------>2M
X g= 40*1*2/1*1 =80 gram
<h3><u>Answer;</u></h3>
= 11,460 years
<h3><u>Explanation;</u></h3>
- <em><u>The half life of Carbon-14 is 5,730 years
. Half life is the time taken by a radioactive material to decay by half of its original mass. Therefore, it would take a time of 5730 years for a sample of 100 g of carbon-14 to decay to 50 grams</u></em>
<em>The initial amount of carbon-14 in this case was 1 whole; thus; </em>
<em>1 → 1/2 →1/4</em>
<em>To contain 1/4 of the value, 2 half-lives have passed.
</em>
<em>But, 1 half life = 5,730 years</em>
<em>Therefore; The artifact is is therefore: 2 x 5,730
</em>
<em> = 11,460 years </em>
Answer:
[Na₂CO₃] = 0.094M
Explanation:
Based on the reaction:
HCO₃⁻(aq) + H₂O(l) ↔ CO₃²⁻(aq) + H₃O⁺(aq)
It is possible to find pH using Henderson-Hasselbalch formula:
pH = pka + log₁₀ [A⁻] / [HA]
Where [A⁻] is concentration of conjugate base, [CO₃²⁻] = [Na₂CO₃] and [HA] is concentration of weak acid, [NaHCO₃] = 0.20M.
pH is desire pH and pKa (<em>10.00</em>) is -log pka = -log 4.7x10⁻¹¹ = <em>10.33</em>
<em />
Replacing these values:
10.00 = 10.33 + log₁₀ [Na₂CO₃] / [0.20]
<em> [Na₂CO₃] = 0.094M</em>
<em />
Answer:
Therefore 373 mole of Al produce 746 mole of water.
Explanation:
Given reaction is
3 Al+3NH₄ClO₄→Al₂O₃+AlCl₃+3NO+6H₂O
From the above reaction it is clear that 3 mole of Al produce 6 mole of water.
Therefore
3 mole of Al produce 6 mole of water.
1 mole of Al produce 
mole of water.
373 mole of Al produce 
mole of water.
= 746 mole of water.
Therefore 373 mole of Al produce 746 mole of water.
