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Yuliya22 [10]
3 years ago
14

How many ml of 0.500 m naoh would be required to exactly neutralize 220.0 ml of 0.150 m hcl?

Chemistry
1 answer:
Anni [7]3 years ago
8 0
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You might be interested in
Using the balanced equation below,
Zielflug [23.3K]

Answer:

Mass = 6.538 g

Explanation:

Given data:

Mass of zinc hydroxide produced = 9.65 g

Mass of zinc required = ?

Solution:

Chemical equation:

Zn + 2MnO₂ + H₂O      →      Zn(OH)₂ + Mn₂O₃

Number of moles of zinc hydroxide:

Number of moles = mass/molar mass

Number of moles = 9.65 g/ 99.42 g/mol

Number of moles = 0.1 mol

now we will compare the moles of zinc and zinc hydroxide,

                  Zn(OH)₂           :          Zn

                       1                  :          1

                    0.1                  :         0.1

Mass of zinc required:

Mass = number of moles × molar mass

Mass = 0.1 mol × 65.38 g/mol

Mass = 6.538 g

8 0
3 years ago
Read 2 more answers
What is the capillary rise of ethanol in a glass tube with a 0.1 mm radius if the surface tension of ethanol is 0.032Jm2 and the
iragen [17]

Answer:

Explanation:

Expression for capillary rise is as follows

h = 2T / ρ g r where T is surface tension , ρ is density of liquid and r is radius of capillary tube.

T = .032 J m⁻²

ρ = .71 g / cm³

= 7100 kg / m³

r = .1 x 10⁻³ m = 10⁻⁴ m

h = 2 x .032 / (7100 x 9.8 x 10⁻⁴ )

h = .0092 m

= 9.2 mm .

5 0
2 years ago
The average rate of consumption of br− is 1.86×10−4 m/s over the first two minutes. what is the average rate of formation of br2
Scorpion4ik [409]
By considering the reaction equation is:
5Br(aq)+BrO3(aq)+6H(aq)= 3Br2(aq)+3H2O(l)
when the average rate of consumption of Br = 1.86x10^-4 m/s
So from the reaction equation 
5Br → 3Br2 when we measure the average rate of formation (X) during the same interval So,
∴ 1.86x10^-4/5 = X / 3
∴X = 1.1 x 10^-4 m/s
∴the average rate of formation of Br2 = 1.1x10^-4 m/s


7 0
3 years ago
How much time would it take to distribute one avagadro's number of wheat grains if 10^10 grains are A)1.9*10^2 years B)1.9*10^10
Makovka662 [10]

Answer:

It takes  1.9 \times 10^{6} years to distribute all the grains.

Explanation:

In one second, 10^{10} grains of wheat are distributed.

We are supposed to find the time it would take to Distribute Avogadro number of grains.

1 avogadro number = 6.022 \times 10^{23}

Number of grains distributed in 1 day = 86400 \times 10^{10}

                                                             = 8.64 \times 10^{14}

Number of grains distributed in 1 year= 8.64 \times 10^{14} \times 365

                                 = 3.1536 \times 10^{17}

Time taken = \frac{Number of grains to be distributed}{grains distributed in 1 year}

            = \frac {6.022 \times 10^{23}}{3.1536\times 10^{17}}

            = 1.9 \times 10^{6}

7 0
3 years ago
That's how you can
kirza4 [7]
2)8/8-9_12-/78)022-/7/$
6 0
3 years ago
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