Answer:
e must have the charge of the particle
Explanation:
In this experiment, the particles that the cathode rays are found where from an electric field and another magnetic field, for the particle to pass without deviating the magnetic force must have the same modulus of the entricar force, and be in the opposite direction.
the expression for the magnetic force is
F_m = q v xB
the expression for the electric force is
F_e = q E
when warning the check two formulas we must have the charge of the particle
When a battery is connected to a circuit, the electrons from the anode travel through the circuit toward the cathode in a direct circuit. The voltage of a battery is synonymous with its electromotive force, or emf. This force is responsible for the flow of charge through the circuit, known as the electric current.
Answer:
Use the drop-down menus to answer each question.
Which runner finished the 100 m race in the least amount of time?
✔ Ming
Which runner stopped running for a few seconds during the race?
✔ Chloe
At what distance did Anastasia overtake Chloe in the race?
✔ 40 m
Answer:
E1_max = 866 V/m...................................... option D
Explanation:
We know that for linearly polarized light, relation between intensity and electric field is given by:
I_avg = (1/2)*c*e0*E_max^2
I_avg = (1/2)*3*10^8*8.854*10^-12*1000^2
I_avg = 1328.1 W/m^2
Now given that light is already polarized, So Using Malus's law, Intensity of light after passing through polarizer will be:
I1 = I_avg*(cosФ )^2
Ф = 30 deg, So
I1 = 1328.1*(cos 30 deg)^2 = 996.1 W/m^2
Now electric field corresponding to above Intensity will be:
I1 = (1/2)*c*e0*E1_max^2
E1_max = sqrt (2*I1/(c*e0))
E1_max = sqrt (2*996.1/(3*10^8*8.854*10^-12))
E1_max = 866 V/m