<span>Place a test charge in the middle. It is 2cm away from each charge.
The electric field E= F/Q where F is the force at the point and Q is the charge causing the force in this point.
The test charge will have zero net force on it. The left 30uC charge will push it to the right and the right 30uC charge will push it to the left. The left and right force will equal each other and cancel each other out.
THIS IS A TRICK QUESTION.
THe electric field exactly midway between them = 0/Q = 0.
But if the point moves even slightly you need the following formula
F= (1/4Piε)(Q1Q2/D^2)
Assume your test charge is positive and make sure you remember two positive charges repel, two unlike charges attract. Draw the forces on the test charge out as vectors and find the magnetude of the force, then divide by the total charge to to find the electric field strength:)</span>
The amount of energy needed is 2093 J
Explanation:
The amount of energy needed to increase the temperature of a substance by
is given by the equation

where
m is the mass of the substance
C is its specific heat capacity
is the increase in temperature
For the water in this problem, we have
m = 50.0 g = 0.050 kg
(specific heat capacity of water)

Therefore, the amount of energy needed is

Learn more about specific heat capacity:
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Let us situate this on the x axis, and let our uniform line of charge be positioned on the interval <span>(−L,0]</span> for some large number L. The voltage V as a function of x on the interval <span>(0,∞)</span> is given by integrating the contributions from each bit of charge. Let the charge density be λ. Thus, for an infinitesimal length element <span>d<span>x′</span></span>, we have <span>λ=<span><span>dq</span><span>d<span>x′</span></span></span></span>.<span>V(x)=<span>1/<span>4π<span>ϵ0</span></span></span><span>∫line</span><span><span>dq/</span>r</span>=<span>λ/<span>4π<span>ϵ0</span></span></span><span>∫<span>−L</span>0</span><span><span>d<span>x/</span></span><span>x−<span>x′</span></span></span>=<span>λ/<span>4π<span>ϵ0</span></span></span><span>(ln|x+L|−ln|x|)</span></span>
Answer:
10.32874 m
Explanation:
= Atmospheric pressure = 101325 Pa
g = Acceleration due to gravity = 9.81 m/s²
h = Height of water
= Density of water = 1000 kg/m³
If the walls of the tube do not collapse that means that maximum pressure inside will be the atmospheric pressure
Atmospheric pressure is given by

The maximum height to which Superman can lift the water is 10.32874 m
On the Moon there is no atmosphere so no atmospheric pressure which means when the straw is placed in water water will not rise in the tube.