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taurus [48]
3 years ago
8

Which one of the following devices converts radioactive emissions to light for detection?

Physics
1 answer:
Finger [1]3 years ago
6 0

the radiotracer converts radioactive emissions to light for detection. the answer is D.

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What electromagnetic waves are used in these applications?
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Diagnosing illnesses: Radio Waves
Warming and cooking food: microwaves
Transmitting data from remote controls to televisions: infrared waves
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3 years ago
Defined the term electromagnetic induction and explain how a generator uses electromagnetic induction​
tatuchka [14]

Is the production of electricity by magnetic field.

There are two types of generator which is <u>D</u><u>.</u><u>C</u><u> </u>generator . And A.C <em>g</em><em>e</em><em>n</em><em>e</em><em>r</em><em>a</em><em>t</em><em>o</em><em>r</em>

A.C gen consist of rectangular coil,brushes and permanent magnet

According to the external force mechanical energy used to rotate coil, due to magnetic flux produced by permanent magnet create induced current, this is to according to flemmings right hand rule of electromagnetic induction the rotating coil will produce current

I hope that will help.

8 0
3 years ago
You stand on a merry-go-round which is spinning at f = 0.25 revolutions per second. You are R = 200 cm from the center. (a) Find
wariber [46]

Answer:

a) ω = 9.86 rad/s

b) ac = 194. 4 m/s²

c) minimum coefficient of static friction, µs = 19.8

Explanation:

a) angular speed, ω = 2πf, where f is frequency of revolution

1 rps = 6.283 rad/s, π = 3.142

ω = 2 * 3.14 * 0.25 * 6.28

ω = 9.86 rad/s

b) centripetal acceleration, a = rω²

where r is radius in meters; r = 200 cm or 2 m

a = 2 * 9.86²

a = 194. 4 m/s²

c) µs = frictional force/ normal force

frictional force = centripetal force = ma; where a is centripetal acceleration

normal force = mg; where g = 9.8 m/s²

µs = ma/mg = a/g

µs = 194.4 ms⁻²/9.8 ms⁻²

c) minimum coefficient of static friction, µs = 19.8

5 0
3 years ago
The Shinkansen (bullet train in Japan) makes a trip from Tokyo Station to Kyoto station in 2 hours and 14 min. The distance trav
11Alexandr11 [23.1K]

Answer:

v =  57.2 m/s

Explanation:

The average velocity of the train can be defined as the total distance covered by the train divided by the time taken by the train to cover that distance. Therefore, we will use the following formula to find the average velocity of the train:

v = s/t

where,

s = distance covered = 460 km = (460 km)(1000 m/1 km) = 4.6 x 10⁵ m

t = time taken to cover the distance = 2 h 14 min

Now, we convert it into minutes:

t = (2 h)(60 min/1 h) + 14 min

t = 120 min + 14 min = (134 min)(60 s/1 min)

t = 8040 s

Therefore, the value of velocity will be:

v = (4.6 x 10⁵ m)/8040 s

<u>v =  57.2 m/s</u>

7 0
3 years ago
Protons and neutrons grouped in a specific pattern
alexgriva [62]
Answer b protons and electrons
5 0
3 years ago
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