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Zigmanuir [339]
3 years ago
7

A 250 g blob of clay moves with a speed of 15 m/s towards a 400 g cart that is initially at rest. a). What is the momentum of th

e system before the blob of clay strikes the cart? b). What must be the momentum of the system after they come together? ( Please note, a response of "the same " is insufficient and will result in minimal credit). c. If the blob of clay sticks to the cart, with what speed will the clay and cart move after they come together?
Physics
1 answer:
stiv31 [10]3 years ago
7 0

Hi there!

a)

We can use the following equation to solve for the momentum. Remember that momentum is ALWAYS CONSERVED.

p = m · v

Plug in the given values:

p = (.250) · 15 = 3.75 kgm/s

b)

The momentum of the system AFTER the collision will be the same because of a CONSERVATION OF MOMENTUM.

p_i = p_f

c)

We know that by the conservation of momentum:

m₁v₁ + m₂v₂ = m₁v₁ '+ m₂v₂'

The second object (cart) is originally at rest, and the two objects move together after the collision, so:

m₁v₁ = (m₁ + m₂)vf

Solve by plugging in values:

(.250)(15)/(.250 + .400) = vf = 5.769 m/s

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The 102N acting on the ropes being pulled by eric and kim have some of that force acting horizontally, and some of it vertically. By visualizing it as a right angled triangle, with the hypotenuse the length of the diagonal force, and each side the length of the horizontal and vertical forces, you can use trigonometry to calculate the length of the vertical force. You are told that it is at an angle of 30 with the vertical rope, therefore you know the length of the hypotenuse, and the angle between it and the vertical force, so using trig: (vertical force=x)
x/102=cos(30)
x=102*cos(30)
x=88.33
Therefore the diagonal ropes give a vertical force of 88.33N, and the centre rope, as it acts vertically, gives a vertical force of all 102N. The total:
88.33*2+102=278.66N

I don't know if this is very clear, I hope its good enough to help. If you don't understand, just ask, and I can answer any questions!!! :)
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3 years ago
Where does these choices go?
murzikaleks [220]

Answer:

Nothing goes to Kinetic Energy

Both-1, 2, 4

Potential Energy-3 and 5

Explanation:

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3 years ago
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Provide more information please
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3 years ago
Katy works at a pet store, and is in charge of tracking the cat food supply for the morning, afternoon, and evening shifts. Ther
Basile [38]
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4 years ago
Read 2 more answers
How much gravitational force do two lead balls with a mass of 8 kilograms, the centers of mass of which are 17 cm apart, affect
Arisa [49]

Answer:

1.48×10⁻⁷ Newtons

Explanation:

From the question,

According to newton's law of universal gravitation.

F = Gmm'/r²........................ Equation 1

F = gravitational force, G = gravitational constant, m = mass of the first ball, m' = mass of the second ball, r = distance between the balls.

Given: m = m' = 8 kg, r = 17 cm = 0.17 m,

Constant : G = 6.67×10⁻¹¹ Nm²/kg²

Substitute these values into equation 1

F =  (6.67×10⁻¹¹×8×8)/(0.17²)

F = 1.48×10⁻⁷ N

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