A 250 g blob of clay moves with a speed of 15 m/s towards a 400 g cart that is initially at rest. a). What is the momentum of th
1 answer:
Hi there!
a)
We can use the following equation to solve for the momentum. Remember that momentum is ALWAYS CONSERVED.
p = m · v
Plug in the given values:
p = (.250) · 15 = 3.75 kgm/s
b)
The momentum of the system AFTER the collision will be the same because of a CONSERVATION OF MOMENTUM.
c)
We know that by the conservation of momentum:
m₁v₁ + m₂v₂ = m₁v₁ '+ m₂v₂'
The second object (cart) is originally at rest, and the two objects move together after the collision, so:
m₁v₁ = (m₁ + m₂)vf
Solve by plugging in values:
(.250)(15)/(.250 + .400) = vf = 5.769 m/s
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Answer:
= -32.53 m / s
this velocity is directed downwards
Explanation:
This is a free fall exercise, let's use the expression
= v_{oy}^{2} + 2 g (y -yo)
where we are assuming that there is friction with the air, as the body falls its initial velocity is zero
v_{oy} = √ 2g (y - y₀)
let's calculate
v_{y} = √ (2 9.8 (0-54.0))
= -32.53 m / s
this velocity is directed downwards
<h2>Hello!</h2>
The answer is:
The first option, the walker traveled 360m more than the actual distance between the start and the end points.
Why?
Since each block is 180 m long, we need to calculate the vertical and the horizontal distance, in order to calculate how farther did the travel walk between the start and the end points (displacement).
So, calculating we have:
Traveler:
Actual distance between the start and the end point (displacement):
Now, to calculate how much farter did the traveler walk, we need to use the following equation:
Therefore, we have that distance differnce between the distance covered by the walker and the actual distance is 360m.
Hence, we have that the walker traveled 360m more than the actual distance between the start point and the end point.
Have a nice day!