Mem me e m even have. Jags. Shah. Shiv side esicjm is n meh dish so do indbbd
The equation we use is mλ=dsinθ for intensity maximas. We are given at the first maximum (m=1), it occurs at 17.8 degrees. Thus we can solve for d by substituting known values into our equation.
(1) (632.8*10^-9m)=dsin(17.8) => d = 2.07*10^-6m
Next we want to find the angle at the second maximum (m=2) so we need to solve for θ.
(2) (632.8*10^-9m) = (2.07*10^-6m)sinθ
θ=37.69 degrees
Hopes this helps!
P.S. I hope this is right. If not sorry in advance.
B. secondary waves aka shear waves
Answer:
33,02 lb
Explanation:
g_m ≈ 1,62 m/s2
g ≈ 9,81 m/s2
m = 200 lb
m_m = m * g_m / m = 200 * 1,62 / 9,81 = 33,02 lb
