Each of two parents has the genotype green divided by brown, which consists of the pair of alleles that determine eye color, a
nd each parent contributes one of those alleles to a child. Assume that if the child has at least one green allele, that color will dominate and the child's eye color will be green. a. List the different possible outcomes. Assume that these outcomes are equally likely. b. What is the probability that a child of these parents will have the brown divided by brown genotype? c. What is the probability that the child will have green eye color?
In order to solve this you just have to create a punnet square, where the parents are shown to both have brown and green coloured eyes genes, so it would be like this:
Mother: Brown Green
Father↓
Brown Brown-Brown Brown-Green
Green Brown-Green Green-Green
As the instructions say that if any kid had one green allele that would be the dominant, only the Brown-Brown will show the fenotype, so there´s 1/4 chance to happen, or 25%, the other probability of having green eyes is 3/4 or 75%
The transport process that does not requires the consumption of ATP molecules is called as passive transport. The movement of solute molecules along the concentration gradient (from higher concentration to lower concentration) is called diffusion. This process does not requires ATP for the movement of molecules from one place to another.
