Each of two parents has the genotype green divided by brown, which consists of the pair of alleles that determine eye color, a
nd each parent contributes one of those alleles to a child. Assume that if the child has at least one green allele, that color will dominate and the child's eye color will be green. a. List the different possible outcomes. Assume that these outcomes are equally likely. b. What is the probability that a child of these parents will have the brown divided by brown genotype? c. What is the probability that the child will have green eye color?
In order to solve this you just have to create a punnet square, where the parents are shown to both have brown and green coloured eyes genes, so it would be like this:
Mother: Brown Green
Father↓
Brown Brown-Brown Brown-Green
Green Brown-Green Green-Green
As the instructions say that if any kid had one green allele that would be the dominant, only the Brown-Brown will show the fenotype, so there´s 1/4 chance to happen, or 25%, the other probability of having green eyes is 3/4 or 75%
I cant remember the lesson number but if the number of predators increase it would make many animals that are there prey to become scarce in the area the predators are in wich would make many predators starve so in order to avoid they would have to move out across more land to find more food
The children were given the recessive traits from their mother and the dominant traits from their father because the genes mix when they have children.
