All categories

2 years ago

Which variables are involved in understanding Kepler's third law of motion? (1 point)

Physics

2 answers:

Zielflug [23.3K]2 years ago

7 0

The variables which are involved in understanding Kepler's third law of

motion are

Orbital velocity

Distance to sun

<h3 /><h3>What is Kepler's third law of motion?</h3>

Kepler's third law of motion states that the the square of the orbital period of

a planet is proportional to the cube of the semi-major axis of its orbit. He

also inferred that the greater the distance, the slower the orbital velocity.

This thereby makes option D the most appropriate option as it contains the

orbital velocity and distance to sun variables.

Read more about Kepler's third law of motion here brainly.com/question/777046

klasskru [66]2 years ago

5 0

Answer:orbital velocity distance to sun

Explanation:

You might be interested in

A disk of mass M and radius R rotates at angular velocity ω0. Another disk of mass M and radius r is dropped on top of the rotat

AleksandrR [38]

Answer:

$\omega = \frac{(R^2\omega_o}{(R^2 + r^2)}$

Explanation:

As we know that there is no external torque on the system of two disc

then the angular momentum of the system will remains conserved

So we will have

$L_i = L_f$

now we have

$L_i = (\frac{1}{2}MR^2)\omega_o$

also we have

$L_f = (\frac{1}{2}MR^2 + \frac{1}{2}Mr^2)\omega$

now from above equation we have

$(\frac{1}{2}MR^2)\omega_o = (\frac{1}{2}MR^2 + \frac{1}{2}Mr^2)\omega$

now we have

$\omega = \frac{MR^2\omega_o}{(MR^2 + Mr^2)}$

$\omega = \frac{(R^2\omega_o}{(R^2 + r^2)}$

6 0

3 years ago

PLEASE HELP ME

posledela

Low levels of fecal coliform

5 0

3 years ago

Read 2 more answers

How does a helicopter fly ? ( I need it explained in the view of physics)

Zielflug [23.3K]

Answer:

because blades of helicopter create a high pressure difference between lower and higher portion of blade so due to this pressure difference helicopter became able to fly.

Explanation:

for instant answer

join wats up group

just scan it

post question

get answer from trusted experts for free

3 0

3 years ago

Read 2 more answers

An asteroid with a mass of 5.0 x 105 kg collides with the Earth and slides horizontally along the ground without bouncing (not a

V125BC [204]

The strength of the friction doesn't matter. Neither does the distance or the time the asteroid takes to stop. All that matters is that the asteroid has

1/2 (mass) (speed squared)

of kinetic energy when it lands, and zero when it stops.
So

1/2 (mass) (original speed squared)

is the energy it loses to friction in order to come to rest.

8 0

3 years ago

Identify the region in the image where lighter elements, such as hydrogen or helium, are more likely to be found in a liquid or

Annette [7]

Lower in an arrangement

3 0

3 years ago

Read 2 more answers