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3 years ago

Density=2g/mL and volume=20mL what is mass

Physics

2 answers:

leva [86]3 years ago

8 0

Answer:

40g

Explanation:

Mass = density x volume

= 2 x 20

= 40g

8090 [49]3 years ago

3 0

Answer:

m = V × ρ

= 20 milliliter × 2 gram/cubic meter

= 2.0E-5 cubic meter × 2 gram/cubic meter

= 4.0E-5 gram

= 4.0E-8 kilogram

Explanation:

The density of a material, typically denoted using the Greek symbol ρ, is defined as its mass per unit volume.

ρ =

where:

ρ is the density

m is the mass

V is the volume

The calculation of density is quite straightforward. However, it is important to pay special attention to the units used for density calculations. There are many different ways to express density, and not using or converting into the proper units will result in an incorrect value. It is useful to carefully write out whatever values are being worked with, including units, and perform dimensional analysis to ensure that the final result has units of mass volume. Note that density is also affected by pressure and temperature.

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A 2000 N net force will give a car with some amount of mass an acceleration of 4 m/s2

hammer [34]

Answer:

2m/s²

Explanation:

Given parameters:

Net force on the car = 2000N

Acceleration = 4m/s²

Unknown:

Acceleration of a car twice the mass = ?

Solution:

Let us first find the mass of the car;

Force = mass x acceleration

Mass = $\frac{Force }{acceleration}$

Mass = $\frac{2000}{4}$ = 500kg

Now,

whose mass is twice that of the car

Mass of the new car = 2 x 500 = 1000kg

So;

Acceleration = $\frac{Net force }{mass}$

Acceleration = $\frac{2000}{1000}$ = 2m/s²

3 0

2 years ago

The velocity of a passenger relative to a boat is -vpb. The velocity of the boat relative to the river it is moving on is vbr. T

RideAnS [48]

Answer:

vps = vbr + vrs - vpb

Explanation:

If the passenger were at rest, his speed relative to the shore will be identical to the boat's, as follows:
vps = vbr + vrs
As he is moving in a direction opposite to the boat's, his velocity relative to the shore must be less than if he were at rest, in the same quantity that he was moving opposite to the boat, as follows:
vps = vbr+ vrs -vpb

5 0

2 years ago

A 1.50-mm-diameter glass sphere has a charge of + 1.60 nC. What speed does an electron need to orbit the sphere 1.60 mm above th

saveliy_v [14]

Answer :

Velocity will be $3.28\times 10^{-11}m/sec$

Explanation:

We have given glass surface has a diameter of 1.5 mm

And charge q = 1.60 nC

Radius of electrons orbit r = height of electron above surface + radius of sphere = $=1.6+\frac{1.5}{2}=2.35mm = 0.00235m$

Force on electron is given by $F=\frac{1}{4\pi \epsilon _0}\frac{qe}{r^2}$ , here q is charge on sphere and e is charge on electron

$F=\frac{1}{4\pi \epsilon _0}\frac{qe}{r^2}=\frac{kqe}{r^2}=\frac{9\times 10^9\times 1.6\times 10^{-9}\times 1.6\times 10^{-19}}{0.00235^2}=4.172\times 10^{-13}N$