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3 years ago

Density=2g/mL and volume=20mL what is mass

Physics

2 answers:

leva [86]3 years ago

8 0

Answer:

40g

Explanation:

Mass = density x volume

= 2 x 20

= 40g

8090 [49]3 years ago

3 0

Answer:

m = V × ρ

= 20 milliliter × 2 gram/cubic meter

= 2.0E-5 cubic meter × 2 gram/cubic meter

= 4.0E-5 gram

= 4.0E-8 kilogram

Explanation:

The density of a material, typically denoted using the Greek symbol ρ, is defined as its mass per unit volume.

ρ =

where:

ρ is the density

m is the mass

V is the volume

The calculation of density is quite straightforward. However, it is important to pay special attention to the units used for density calculations. There are many different ways to express density, and not using or converting into the proper units will result in an incorrect value. It is useful to carefully write out whatever values are being worked with, including units, and perform dimensional analysis to ensure that the final result has units of mass volume. Note that density is also affected by pressure and temperature.

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Which of these stopped operating in 2011

Vladimir [108]

D. space shuttle program

8 0

4 years ago

Read 2 more answers

A woman lifts her 150 N child up one meter and carries her for a distance of 50 meters to the

Cloud [144]

7500J

Explanation:

Given parameters:

Weight of child = 150N

Height of lifting = 50m

Distance = 50m

Unknown:

Work done by the woman = ?

Solution:

Work done by a body is the force applied to move a body through a given distance.

Work done = Force x distance

Weight is a force impacted by the mass of a body and the gravity on it.

input the parameters:

Work done = 150 x 50 = 7500J

learn more:

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3 0

3 years ago

1. A car is traveling at 36 m/s hits a tree and comes to rest in 0.05 seconds.

QveST [7]

Answer: a. -720m/s^2

b. Yes, airbags will deploy

Explanation:

The formula for acceleration is:

= (Final velocity - Initial velocity)/Time

Final velocity = 0m/s

Initial velocity = 36m/s

Time taken = 0.05s

= (Final velocity - Initial velocity)/Time

= (0 - 36)/0.05

= -36/0.05

= -720m/s^2.

Since it's negative, it shows that there was a deceleration.

2. Yes the airbag will deploy since the acceleration gotten is more than -600 m/s^2.

3 0

4 years ago

The "steam" above a freshly made cup of instant coffee is really water vapor droplets condensing after evaporating from the hot

KiRa [710]

Answer:

$T_{f}$ = 85.7 ° C

Explanation:

For this exercise we will use the calorimetry heat ratios, let's start with the heat lost by the evaporation of coffee, since it changes from liquid to vapor state

Q₁ = m L

Where m is the evaporated mass (m = 2.00 103-3kg) and L is 2.26 106 J / kg, where we use the latent heat of the water

Q₁ = 2.00 10⁻³ 2.26 10⁶

Q1 = 4.52 10³ J

Now the heat of coffee in the cup, which does not change state is

Q coffee = M $c_{e}$ ( $T_{f}$ - $T_{i}$ )

Since the only form of energy transfer is terminated, the heat transferred is equal to the evaporated heat

Qc = - Q₁

M ce ( $T_{f}$ - $T_{i}$ ) = - Q₁

The coffee dough left in the cup after evaporation is

M = 250 -2 = 248 g = 0.248 kg

$T_{f}$ -Ti = -Q1 / M $c_{e}$

$T_{f}$ = Ti - Q1 / M $c_{e}$

Since coffee is essentially water, let's use the specific heat of water,

$c_{e}$ = 4186 J / kg ºC

Let's calculate

$T_{f}$ = 90.0 - 4.52 103 / (0.248 4.186 103)

$T_{f}$ = 90- 4.35

$T_{f}$ = 85.65 ° C

$T_{f}$ = 85.7 ° C

5 0

3 years ago

An open container holds ice of mass 0.555 kg at a temperature of -16.6 ∘C . The mass of the container can be ignored. Heat is su

s2008m [1.1K]

Answer: A. 23.59 minutes.

B. 249.65 minutes

Explanation: This question involves the concept of Latent Heat and specific heat capacities of water in solid phase.

Latent heat of fusion is the total amount of heat rejected from the unit mass of water at 0 degree Celsius to convert completely into ice of 0 degree Celsius (and the heat required for vice-versa process).

Specific heat capacity of a substance is the amount of heat required by the unit mass of a substance to raise its temperature by 1 kelvin.

Here, given that:

mass of ice, m= 0.555 kg

temperature of ice, T= -16.6°C

rate of heat transfer, $q=820 J.min^{-1}$

specific heat of ice, $c_{i}= 2100 J.kg^{-1}.K^{-1}$

latent heat of fusion of ice, $L_{i}=334\times10^{3}J.kg^{-1}$

Asked:

1. Time require for the ice to start melting.

2. Time required to raise the temperature above freezing point.

Sol.: 1.

We have the formula:

$Q=mc\Delta T$

Using above equation we find the total heat required to bring the ice from -16.6°C to 0°C.

$Q= 0.555\times2100\times16.6$

$Q= 19347.3 J$

Now, we require 19347.3 joules of heat to bring the ice to 0°C and then on further addition of heat it starts melting.

∴The time required before the ice starts to melt is the time required to bring the ice to 0°C.

$t=\frac{Q}{q}$

$=\frac{19347.3}{820}$

= 23.59 minutes.

Sol.: 2.

Next we need to find the time it takes before the temperature rises above freezing from the time when heating begins.

Now comes the concept of Latent heat into the play, the temperature does not starts rising for the ice as soon as it reaches at 0°C it takes significant amount of time to raise the temperature because the heat energy is being used to convert the phase of the water molecules from solid to liquid.

From the above solution we have concluded that 23.59 minutes is required for the given ice to come to 0°C, now we need some extra amount of energy to convert this ice to liquid water of 0°C.

We have the equation: latent heat, $Q_{L}= mL_{i}$

$Q_{L}= 0.555\times334\times10^{3}= 185370 J$

Now the time required for supply of 185370 J:

$t=\frac{Q_{L}}{q}$

$t=\frac{185370}{820}$

t= 226.06 minutes

∴ The time it takes before the temperature rises above freezing from the time when heating begins= 226.06 + 23.59

= 249.65 minutes

8 0

3 years ago