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3 years ago

Density=2g/mL and volume=20mL what is mass

Physics

2 answers:

leva [86]3 years ago

8 0

Answer:

40g

Explanation:

Mass = density x volume

= 2 x 20

= 40g

8090 [49]3 years ago

3 0

Answer:

m = V × ρ

= 20 milliliter × 2 gram/cubic meter

= 2.0E-5 cubic meter × 2 gram/cubic meter

= 4.0E-5 gram

= 4.0E-8 kilogram

Explanation:

The density of a material, typically denoted using the Greek symbol ρ, is defined as its mass per unit volume.

ρ =

where:

ρ is the density

m is the mass

V is the volume

The calculation of density is quite straightforward. However, it is important to pay special attention to the units used for density calculations. There are many different ways to express density, and not using or converting into the proper units will result in an incorrect value. It is useful to carefully write out whatever values are being worked with, including units, and perform dimensional analysis to ensure that the final result has units of mass volume. Note that density is also affected by pressure and temperature.

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Answer:

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4 years ago

Calculate the current in a circuit if 500 C of charge passes through it in 10 minutes. *

Sloan [31]

Answer:

Choice a. Approximately $0.83\; \rm A$ on average.

Explanation:

The electric current through a wire is the rate at which electric charge flows through a cross-section of this wire.

Assume that electric charge of size $Q$ flowed through a wire cross-section over a period of time $t$ . The average current in that wire would be:

$\displaystyle I = \frac{Q}{t}$ .

For this question:

$Q = 500\; \rm C$ , whereas
$t = 10\; \rm \text{minutes}$ .

Therefore, the average current in this circuit would be:

$\displaystyle I = \frac{Q}{t} = \frac{500\; \rm C}{10\; \text{minutes}} = 50\; \rm C /\text{minute}$ .

However, the units in the choices are all in $\rm A$ (for Amperes.) One Ampere is equal to one $\rm C / \text{second}$ . It will take some unit conversations to change the unit of $I = 50\; \rm C/ \text{minute}$ (coulombs-per-minute) to coulombs-per-second.

$\begin{aligned}I &= 50\; \rm C/ \text{minute} \\ &= \frac{50\; \rm C}{1\; \rm \text{minute}} \times \frac{1 \; \text{minute}}{60\; \rm \text{seconds}} \approx 0.83\; \rm C/ \text{second} = 0.83 \; \rm A\end{aligned}$ .

Hence, the most accurate choice here would be choice a.

7 0

3 years ago