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saveliy_v [14]
3 years ago
12

The amount of attraction between two masses depends on:

Chemistry
1 answer:
Zinaida [17]3 years ago
5 0

Answer:

The strength of the gravitational force between two objects depends on two factors, mass and distance.

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Methane combines with oxygen in the air to make carbon dioxide and water vapor.
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3 years ago
Read 2 more answers
The mass of 1.49 of H2 gas at stp
FinnZ [79.3K]

Answer:

Explanation:

I'll assume 1.49 is liters.

All gases occupy 22.4 L for each mole of gas at STP.  This makles a very useful, and important, conversion factor:

(22.4L/mole gas) for all gases at STP.

Therefore 1.49L of H2 would be:

(1.49L H2)/(22.4L/mole gas) = 0.0665 moles

The molar mass of H2 is 2, so:

(0.0665 moles)*(2g/mole) = 0.133 grams to 3 sig figs

3 0
3 years ago
Can someone help me to figure out them please
Ronch [10]
2)NCl3
4)N2O3
5)NH3
6)B2H2
7)K3P
8)OF2
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5 0
3 years ago
2. Answer the following questions about a sample of calcium phosphate:
weqwewe [10]

Answer:

a) <u>310.18 g/mol</u>

<u>b) 4.352 moles Ca3(PO4)2</u>

<u>c) 2.6 * 10^24 molecules</u>

<u>d) 5.24 * 10^24 P atoms</u>

<u>e)13.056 moles Ca</u>

<u>f)</u>10825.3 grams

Explanation:

Step 1: Data given

Atomic mass of Ca = 40.08 g/mol

Atomic mass of P = 30.97 g/mol

Atomic mass of O = 16.0 g/mol

Step 2: Calculate molecular weight of Ca3(PO4)2

Molecular weight of Ca3(PO4)2 = 3*atomic mass of Ca + 2* atomic mass of P and 8* atomic mass of O

Molecular weight of Ca3(PO4)2 = 3*40.08 + 2*30.97 + 8*16.0  =<u> 310.18 g/mol</u>

Step 3: Calculate moles of Ca3(PO4)2 in 1350 grams

Moles Ca3(PO4)2 = mass Ca3(PO4)2 /molar mass

Moles Ca3(PO4)2 = 1350 grams / 310.18 g/mol

Moles Ca3(PO4)2 = <u>4.352 moles</u>

Step 4: Calculate molecules in 1350 grams

Molecules = moles * number of Avogadro

Molecules = 4.352 moles * 6.02 * 10^23

Molecules = <u>2.6 *10^24 molecules</u>

<u />

Step 5: Calculate moles Phosphorus

For 1 mol Ca3(PO4)2 we need 2 moles P

For 4.352 moles Ca3(PO4)2 we have 2*4.352 = 8.704 moles

Step 6: Calculate P atoms

Atoms P = 8.704 moles * 6.02*10^23

Atoms P =<u> 5.24 * 10^24 P atoms</u>

<u />

Step 7: Calculate moles Calcium in 1350 grams

For 1 mol Ca3(PO4)2 we have 3 moles Ca

For 4.352 moles we have 3*4.352 = <u>13.056 moles Ca</u>

<u />

<u />

<u>Step 8:</u> Calculate mass of 2.1 * 10^25 molecules of Ca3(PO4)2

Moles Ca3(PO4)2 = 2.1 * 10^25 / 6.02 * 10^23

Moles Ca3(PO4)2 = 34.9 moles

Mass Ca3(PO4)2 = 34.9 moles * 310.18 g/mol

Mass Ca3(PO4)2 = 10825.3 grams

4 0
3 years ago
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