You have a solid square copper ground support, 2 inch per side X 6 inches tall, and it is loaded axially (long axis)with 1600 po
unds (force). You have instrumented one rectangular flat of the support with 2 strain gages (half bridge construction). The strain gages are made from modified Karma - Alloy K, that has a nominal resistance R0 = 350Ω, and that has a gage factor GF = 2.107.
1 answer:
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Answer:
119.35 mm
Explanation:
Given:
Inside diameter, d = 100 mm
Tensile load, P = 400 kN
Stress = 120 MPa
let the outside diameter be 'D'
Now,
Stress is given as:
stress = Load × Area
also,
Area of hollow pipe =
or
Area of hollow pipe =
thus,
400 × 10³ N = 120 ×
or
D² = tex]\frac{400\times10^3+30\pi\times10^4}{30\pi}[/tex]
or
D = 119.35 mm
Answer:
A) attached below
B) 743 KJ
C) 1.8983 KJ/K
Explanation:
A) Diagram of system schematic and set up states
attached below
<u>B) Calculate the amount of work received from the paddle wheel </u>
assuming ideal gas situation
v1 = v2 ( for a constant volume process )
work generated by paddle wheel = system internal energy
dw = mCv dT . where ; Cv = 0.743 KJ/kgk
= 5 * 0.743 * ( 500 - 300 )
= 3.715 * 200 = 743 KJ
<u>C) calculate the amount of entropy generated ( KJ/K )</u>
S2 - S1 = 1.8983 KJ/K
attached below is the detailed solution
