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3 years ago

What is the density of this liquid that has a mass of 300g and volume 600ml.

Physics

2 answers:

8_murik_8 [283]3 years ago

8 0

Answer:

0.5

Explanation:

D = M / V

You divide 300g by 600ml and you get 0.5

(✿◠‿◠)

Katen [24]3 years ago

5 0

la respuesta es

0.5

espero que te sirva

:-)

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Mnenie [13.5K]

Answer:

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30 -30 is already equal to zero, so the answer should be 0

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3 years ago

A car movingin a straight line starts at x = 0 at t = 0. It passes the point x = 25.0 m with a speed of 11.0 m????s at t = 3.00s

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Answer:

Part a)

at t = 3.00 s

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at t = 20.0 s

$v = 19.25 m/s$

Part b)

at t = 3.00 s

$a = 3.67 m/s^2$

at t = 20.0 s

$a = 2.25 m/s^2$

Explanation:

The car starts at x = 0

Part a)

Now at t = 3.00 s

the position of the car is given as x = 25 m and its speed is given as v = 11 m/s

Now for average velocity we have

$v = \frac{displacement}{time}$

$v = \frac{25 - 0}{3}$

$v = 8.33 m/s$

Now for average acceleration we have

$a = \frac{v - 0}{t}$

$a = \frac{11 - 0}{3}$

$a = 3.67 m/s^2$

Part b)

Now at t = 20.0 s

the position of the car is given as x = 385 m and its speed is given as v = 45 m/s

Now for average velocity we have

$v = \frac{displacement}{time}$

$v = \frac{385 - 0}{20}$

$v = 19.25 m/s$

Now for average acceleration we have

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3 years ago

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stealth61 [152]

Answer:

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(b) $a_s=0.13\frac{m}{s^2}$

Explanation:

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$a_s=\frac{F}{m_s}\\a_s=\frac{5.2N}{8.4kg}\\a_s=0.62\frac{m}{s^2}$

(b) According to Newton's third law, the force that the sled exerts on the girl is equal in magnitude but opposite in the direction of the force that the girl exerts on the sled:

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For the girl, we have $x_0=0$ and $v_0=0$ . So:

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For the sled, we have $v_0=0$ . So:

$x_f_s=x_0_s-\frac{a_st^2}{2}(2)$

When they meet, the final positions are the same. So, equaling (1) and (2) and solving for t:

$x_0_s-\frac{a_st^2}{2}=\frac{a_st^2}{2}\\t^2(a_g+a_s)=2x_0_s\\t=\sqrt{\frac{2x_s_0}{a_g+a_s}}\\t=\sqrt{\frac{2(15m)}{0.13\frac{m}{s^2}+0.62\frac{m}{s^2}}}\\t=6.32s$

Now, we solve (1) for $x_f_g$

$x_f_g=\frac{0.13\frac{m}{s^2}(6.32s)^2}{2}\\x_f_g=2.6m\\x_f=2.6m$

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