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AysviL [449]
3 years ago
13

The circumference of a bicycle wheel is 2 meters. if it rotates at 1 revolution per second then its linear speed is

Physics
1 answer:
tester [92]3 years ago
6 0
Given:
Circumference = 2 m
Angular speed,  ω = 1 rev/s = 2π radians/s

If the radius is r, then
2πr = 2 
r = 1/π m

The linear (tangential) speed is
v = rω
   = (1/π m)*(2π rad/s) = 0.5 m/s

Answer: 0.5 m/s
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How many protons are in Calcium? (* Hint: The Atomic number of Calcium is 20).
ryzh [129]

Answer:

The answer to your question is: 20

Explanation:

Atomic number is the number of proton and atom has. Each element has a specific number of protons, if the number of protons change, then this is a new element.

Mass number is the number of protons and neutrons and atom has.

                       Mass number = protons + neutrons

Data

Number of protons = ?

Atomic number = 20

Then,

           atomic number = number of protons = 20

3 0
2 years ago
How many minerals are found in earths crust ?
Damm [24]
You can find your answer here www.rsc.org/education/teachers/resources/jesei/minerals/students.htm
5 0
3 years ago
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You set out to design a car that uses the energy stored in a flywheel consisting of a uniform 80-kg cylinder of radius r that ha
Oliga [24]
E = 300km * 2000J/km = 600000J

The rotational energy is given by:
E = 0.5 * I * ω² 

I for a uniform cylinder is given by:
I  = 0.5 * m * r²

Resulting equation:
E = 0.25 * m * r² * ω²

Given values:
ω = 430 rev/s = 430 * 2π / s
E = 600000

Solve for r.
8 0
2 years ago
Which of the following statements is correct about air temperature? When air temperature is higher, the weather is warmer. Warm
-BARSIC- [3]

Answer:

When air temperature is higher, the weather is warmer.

8 0
3 years ago
Ball 1 travels with a momentum of 48.0 kg-m/s east and strikes Ball 2, which is initially at rest.. Ball 1 separates at an angle
vladimir1956 [14]

Answer:

Momentum of 2nd ball is

P = 31.6 kg m/s

direction is given as

\theta = -37.66 degree

Explanation:

As we know that there is no external force on the system of balls so momentum before and after collision will be conserved

So we have

P_i = 48 \hat i + 0

now after collision momentum of two balls is must be same as initial

so we have

P_i = P_f

48\hat i = (30 cos40 \hat i + 30 sin40\hat j) + (P_{2x}\hat i + P_{2y}\hat j)

so we have

48 = 23 + P_{2x}

P_{2x} = 25 kg m/s

for other component we have

0 = 19.3 + P_{2y}

P_{2y} = -19.3 kg m/s

Momentum of 2nd ball is given as

P = \sqrt{P_2x}^2 + P_{2y}^2}

P = 31.6 kg m/s

direction is given as

tan\theta = \frac{P_{2y}}{P_{2x}}

tan\theta = \frac{-19.3}{25}

\theta = -37.66 degree

5 0
2 years ago
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