Answer:
Check the explanation
Explanation:
given
R = 1.5 cm
object distance, u = 1.1 cm
focal length of the ball, f = -R/2
= -1.5/2
= -0.75 cm
let v is the image distance
use, 1/u + 1/v = 1/f
1/v = 1/f - 1/u
1/v = 1/(-0.75) - 1/(1.1)
v = -0.446 cm <<<<<---------------Answer
magnification, m = -v/u
= -(-0.446)/1.1
= 0.405 <<<<<<<<<---------------Answer
The image is virtual
The image is upright
given
R = 1.5 cm
object distance, u = 1.1 cm
focal length of the ball, f = -R/2
= -1.5/2
= -0.75 cm
let v is the image distance
use, 1/u + 1/v = 1/f
1/v = 1/f - 1/u
1/v = 1/(-0.75) - 1/(1.1)
v = -0.446 cm <<<<<---------------Answer
magnification, m = -v/u
= -(-0.446)/1.1
= 0.405 <<<<<<<<<---------------Answer
Kindly check the diagram in the attached image below.
Answer:

Explanation:
The angular acceleration is:


And the angular deceleration is:


The total number of revolutions is:



Answer:

Explanation:
In this question we have given
mass of airplane=.6 Kg
Radius of horizontal circle,r=6m
Time taken to complete 1.6 revolution=5s
Therefore time taken to complete 1 revolution, t=
t=3.1 s
We have to find the speed of airplane
We will first find the distance covered by airplane in tracing one circle which is equal to circumference of circle
We know that
Circumference,d = 
or 

We know that speed=
............(1)
Put value of d and t in equation 1
speed=
