1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
JulijaS [17]
2 years ago
11

If 0.38 M of an aqueous solution of magnesium nitrate hexahydrate (Mg(NO3)2 ᐧ 6H2O) was prepared in the laboratory, how many mL

of the solution would you need to obtain 4.871 grams of this solute?
Chemistry
2 answers:
Rom4ik [11]2 years ago
4 0

Answer:

The correct answer is 49.994 ml (≅ 50 ml)

Explanation:

From the definition of molarity, we know that in a 0.38 M solution there are 0.38 mol of magnesium nitrate hexahydrate per liter of solution:

0.38 M= 0.38 mol / L

The first step to solve the problem is to convert the moles of solute to mass (in grams) by using the molecular weight of Mg(NO₃)₂.6H₂O.

Molecular weight of Mg(NO₃)₂.6H₂O= 256.41 g/mol (from the molar mass of the elements).

mass of Mg(NO₃)₂.6H₂O = 0.38 mol x 256.41 g/mol= 97.43 g

So, there are 97.43 g of Mg(NO₃)₂.6H₂O in 1 L of solution (1 L= 1000 ml). We need to know in <u>how many ml of this solution a mass of 4.871 g is contained</u>, so we write the relations and calculate x (in ml):

97.43 g Mg(NO₃)₂.6H₂O --------------------  1000 ml (= 1 L)

4.871 g Mg(NO₃)₂.6H₂O --------------------- x

x= 4.871 g x 1000 ml / 97.43 g= 49.994 ml

uranmaximum [27]2 years ago
3 0

Answer:

50 mL

Explanation:

Given data

  • Molar concentration (M): 0.38 M
  • Mass of solute: 4.871 g
  • Molar mass of the solute: 256.41 g/mol

We can find the required volume using the following expression.

M = mass of solute / molar mass of solute × liters of solution

liters of solution = mass of solute / molar mass of solute × M

liters of solution = 4.871 g / 256.41 g/mol × 0.38 mol/L

liters of solution = 0.050 L = 50 mL

You might be interested in
if 334.6 g of phosphoric acid is reacted with excess potassium hydroxide. the final mass K3PO4 produced is found to be 248g. wha
Orlov [11]

Answer:

                     %age Yield  =  34.21 %

Explanation:

                   The balance chemical equation for the decomposition of KClO₃ is as follow;

                            3 KOH + H₃PO₄ → K₃PO₄ + 3 H₂O

Step 1: Calculate moles of H₃PO₄ as;

Moles = Mass / M/Mass

Moles = 334.6 g / 97.99 g/mol

Moles = 3.414 moles

Step 2: Find moles of K₃PO₄ as;

According to equation,

                 1 moles of H₃PO₄ produces  =  1 moles of K₃PO₄

So,

              3.414 moles of H₃PO₄ will produce  =  X moles of K₃PO₄

Solving for X,

                      X = 1 mol × 3.414 mol / 1 mol

                      X = 3.414 mol of K₃PO₄

Step 3: Calculate Theoretical yield of K₃PO₄ as,

Mass = Moles × M.Mass

Mass = 3.414 mol × 212.26 g/mol

Mass = 724.79 g of K₃PO₄

Also,

%age Yield  =  Actual Yield / Theoretical Yield × 100

%age Yield  =  248 g / 724.79 × 100

%age Yield  =  34.21 %

3 0
3 years ago
When considering light moving through a diffraction grating, you should treat the light as what?
liraira [26]

Answer:

A particle

Explanation:

Modern quantum theory holds that light has both wave-like and particle-like properties. When the length scales involved are large compared to the wavelengths of light (ex., forming images with thin lenses), the

particle nature of light dominates.

5 0
3 years ago
Read 2 more answers
12.2 scientific notation
Nadya [2.5K]

This would be 1.22 x 10^1

You simply move the decimal.

If this helped you, please list me as brainliest!

3 0
2 years ago
Given these reactions, X ( s ) + 1 2 O 2 ( g ) ⟶ XO ( s ) Δ H = − 668.5 k J / m o l XCO 3 ( s ) ⟶ XO ( s ) + CO 2 ( g ) Δ H = +
qwelly [4]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is -1052.8 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

X(s)+\frac{1}{2}O_2(g)+CO_2(g)\rightarrow XCO_3(s)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) X(s)+\frac{1}{2}O_2(g)\rightarrow XO(s)    \Delta H_1=-668.5kJ

(2) XCO_3(s)\rightarrow XO(s)+CO_2     \Delta H_2=+384.3kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[1\times \Delta H_1]+[1\times (-\Delta H_2)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-668.5))+(1\times (-384.3))=-1052.8kJ

Hence, the \Delta H^o_{rxn} for the reaction is -1052.8 kJ.

7 0
3 years ago
Select the correct answer. Given: 2Al + 6HCl → 2AlCl3 + 3H2 If the chemical reaction produces 129 grams of AlCl3, how many grams
ivann1987 [24]

The reaction produces 2.93 g H₂.

M_r:                        133.34  2.016

        2Al + 6HCl → 2AlCl₃ + 3H₂

<em>Moles of AlCl₃</em> = 129 g AlCl₃ × (1 mol AlCl₃/133.34 g AlCl₃) = 0.9675 mol AlCl₃

<em>Moles of H₂</em> = 0.9675 mol AlCl₃ × (3 mol H₂/2 mol AlCl₃) = 1.451 mol H₂

<em>Mass of H₂</em> = 1.451 mol H₂ × (2.016 g H₂/1 mol H₂) = 2.93 g H₂

7 0
3 years ago
Other questions:
  • How many cu atoms are present in a piece of sterlingsilver jewelry weighing 33.24 g ? (sterling silver is a silver–copper alloy
    12·1 answer
  • If you could help it would be awsome!!!!!
    7·2 answers
  • Characteristic 1: a scar due to an injury
    7·2 answers
  • A sample of uranium ore contains 6.73 mg of 238U and 3.22 mg of 206Pb. Assuming all of the lead arose from the decay of the uran
    13·1 answer
  • Which of the following is best described by the term macroscopic?
    10·1 answer
  • Qué concluyó Proust en relación a la ley de las proporciones definidas?
    12·1 answer
  • When salt dissolves in water:
    7·1 answer
  • The orbital diagram above is from the element ?
    8·1 answer
  • Please help me with this question! I am a bit stuck.
    10·1 answer
  • List and describe the two major types of plastics.​
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!