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Scorpion4ik [409]
2 years ago
5

Simple carbohydrates, also referred to as sugars, include monosaccharides and disaccharides. Monosaccharides consist of a single

sugar molecule, and disaccharides consist of two molecules of sugar joined together. Complex carbohydrates are larger molecules with many sugar molecules. Choose the correct statement about simple or complex carbohydrates. a) Lactose is a five-carbon monosaccharide found in ribonucleic acid (RNA). b) Sucrose is composed of one glucose molecule and one maltose molecule. c) Glucose, fructose, and galactose each contain 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms. d) Carbohydrates contain carbon, hydrogen, and nitrogen. e) Oligosaccharides and polysaccharides are classified as simple carbohydrates.
Chemistry
1 answer:
erma4kov [3.2K]2 years ago
4 0

Answer:

C is correct

Explanation:

A is wrong.

Lactose is a double sugar or disaccharide.

B. is wrong.

Sucrose is a double sugar as well as maltose . A double sugar is expected to contain 2 simple sugars. Sucrose contain glucose and fructose. Maltose itself is a double sugar.

C.is right

The three are simple sugar and they contain the exact atoms and numbers. In fact they are all isomers and essentially would have the same molecular formula. While glucose and fructose are functional group isomers, glucose and galactose are diastereoisomers.

D. is wrong.

Carbohydrates do not contain nitrogen

E. is wrong.

They are not simple carbohydrates but are polymers.

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A gas sample has a temperature of 22c with an unknown volume. The same gas has a volume of 456 mL when the temperature is 86c wi
tester [92]

Answer:

V₁  = 374.71  mL

Explanation:

Given data:

Initial volume of gas= ?

Initial temperature = 22°C

Final temperature = 86°C

Final volume = 456 mL

Solution:

Initial temperature = 22°C (22+273 = 295 k)

Final temperature = 86°C (86+273 = 359 k)

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₁ = V₂T₁ /T₂

V₁  = 456 mL × 295 K / 359 k

V₁  = 134520 mL.K /  359 k

V₁  = 374.71  mL

3 0
3 years ago
You are performing an experiment that uses 114Ag. 113Ag is radioactive, decays by beta-- emission and has a half-life of 21 minu
maxonik [38]

Answer: The 234.74 grams of sample should be ordered.

Explanation:

Let the gram of  114 Ag to ordered be N_o

The amount required for the beginning of experiment = 0.0575 g

Time requires to ship the sample = 4.2hour = 252 min(1 hr = 60 min)

Half life of the sample ={t_{\frac{1}{2}} = 21 min

\lambda =\frac{0.693}{t_{\frac{1}{2}}}=\frac{0.693}{21 min}=0.033 min^{-1}

\log[N]=\log[N_o]-\frac{\lambda t}{2.303}

\log[0.0575 g]=\log[N_o]-\frac{0.033 min^{-1}\times 252 min}{2.303}

N_o=234.74 grams

The 234.74 grams of sample should be ordered.

4 0
2 years ago
Someone help me plz :))) brainliest
SOVA2 [1]

Answer:

Option 2

Explanation:

3 0
3 years ago
A block is found to have volume of 35.3 cm3. It’s mass is 31.7g. Calculate the density of the block
11111nata11111 [884]

Answer:

<h2>1.11 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =  \frac{35.3}{31.7}  \\  = 1.113564

We have the final answer as

<h3>1.11 g/mL</h3>

Hope this helps you

6 0
2 years ago
Calculate the ratio of effusion rates of cl2 to f2 .
WINSTONCH [101]
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6 0
2 years ago
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