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Scorpion4ik [409]
3 years ago
5

Simple carbohydrates, also referred to as sugars, include monosaccharides and disaccharides. Monosaccharides consist of a single

sugar molecule, and disaccharides consist of two molecules of sugar joined together. Complex carbohydrates are larger molecules with many sugar molecules. Choose the correct statement about simple or complex carbohydrates. a) Lactose is a five-carbon monosaccharide found in ribonucleic acid (RNA). b) Sucrose is composed of one glucose molecule and one maltose molecule. c) Glucose, fructose, and galactose each contain 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms. d) Carbohydrates contain carbon, hydrogen, and nitrogen. e) Oligosaccharides and polysaccharides are classified as simple carbohydrates.
Chemistry
1 answer:
erma4kov [3.2K]3 years ago
4 0

Answer:

C is correct

Explanation:

A is wrong.

Lactose is a double sugar or disaccharide.

B. is wrong.

Sucrose is a double sugar as well as maltose . A double sugar is expected to contain 2 simple sugars. Sucrose contain glucose and fructose. Maltose itself is a double sugar.

C.is right

The three are simple sugar and they contain the exact atoms and numbers. In fact they are all isomers and essentially would have the same molecular formula. While glucose and fructose are functional group isomers, glucose and galactose are diastereoisomers.

D. is wrong.

Carbohydrates do not contain nitrogen

E. is wrong.

They are not simple carbohydrates but are polymers.

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Answer: -

C) because the moon rotates once on its axis in the same time that it takes to revolve around the earth

Explanation: -

The moon rotates about it's axis one full time at about the same time as it takes to rotate around the earth.

This leads to only one side of the moon always appearing to Earth, called the near side.

One side of the moon is always not seen from the earth. It is called the far side of the moon.

Thus we can never see the far side of the moon because the moon rotates once on its axis in the same time that it takes to revolve around the earth

4 0
3 years ago
Which of the following is not an indication of a chemical reaction?
amm1812
Formation of a precipitate
4 0
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How do scientists define temperature
kotegsom [21]

A measure of the ability of a substance, or more generally of any physical system, to transfer heat energy to another physical system. The temperature of a substance is closely related to the average kinetic energy of its molecules.

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7 0
3 years ago
Read 2 more answers
Determine the mass (in grams) of 8.02 x 1024 atoms of mercury (Hg).
Virty [35]
<h3>Answer:</h3>

2670 g Hg

<h3>General Formulas and Concepts: </h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation: </h3>

<u>Step 1: Define</u>

8.02 × 10²⁴ atoms Hg

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Hg - 200.59 g/mol

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 8.02 \cdot 10^{24} \ atoms \ Hg(\frac{1 \ mol \ Hg}{6.022 \cdot 10^{23} \ atoms \ Hg})(\frac{200.59 \ g \ Hg}{1 \ mol \ Hg})
  2. Divide/Multiply:                                                                                               \displaystyle 2671.42 \ g \ Hg

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

2671.42 g Hg ≈ 2670 g Hg

3 0
3 years ago
Calculate the pH after 10 mL of 1.0 M sodium hydroxide is added to 60 mL of 0.5M acetic acid.
baherus [9]

Explanation:

It is given that the total volume is (10 mL + 60 mL) = 70 mL.

Also, it is known that M_{1}V_{1} = M_{2}V_{2}

Where,    V_{1} = total volume

               V_{2} = initial volume

Therefore, new concentration of CH_{3}COOH = \frac{M_{2}V_{2}}{V_{1}}

                                        = \frac{60 \times 0.5}{70}

                                        = 0.43 M

New concentration of NaOH = \frac{M_{2}V_{2}}{V_{1}}

                                               = \frac{10 \times 1.0}{70}

                                               = 0.14 M

So, the given reaction will be as follows.

              CH_{3}COOH + OH^{-} \rightarrow CH_{3}COO^{-} + H_{2}O

Initial:             0.43          0.14                     0

Change:          -0.14        -0.14                    0.14

Equilibrium:    0.29          0                       0.14

As it is known that value of pK_{a} = 4.74

Therefore, according to Henderson-Hasselbalch equation calculate the pH as follows.

           pH = pK_{a} + log \frac{[CH_{3}COO^{-}]}{[CH_{3}COOH]}

                 = 4.74 + log \frac{0.14}{0.29}

                 = 4.74 + (-0.316)

                 = 4.42

Therefore, we can conclude that the pH of given reaction is 4.42.

6 0
3 years ago
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