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Aneli [31]
3 years ago
8

Several important physical needs that organisms receive from the environment are:

Chemistry
1 answer:
Gemiola [76]3 years ago
7 0

Answer:

water,minerals carbon dioxide, and oxygen

Explanation:

We answered it on my little brothers quiz, and we got a 100%!!!

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The pressure in a cylinder of nitrogen continuously decreases as a gas is released from it. On the other hand, a cylinder of pro
Juli2301 [7.4K]

Answer:

Explanation:

Nitrogen gas in nitrogen cylinder is in gaseous form only . So when gas is released , pressure decreases because moles of  gas in the cylinder decreases .

Propane gas in cylinder is in liquified form . The gas is partially in gaseous and liquid form . So when gas is released outside , pressure decreases inside but due to low pressure , some liquid form is converted into gaseous form which restores the pressure of gas inside cylinder . Hence , the pressure of gas remains unchanged inside cylinder.  

4 0
3 years ago
Given the speed of light as 3.0 × 108 m/s, calculate the wavelength of the electromagnetic radiation whose frequency is 7.5 × 10
arlik [135]
Wavelength= velocity/frequency
wavelength= (3.0 x 10^8m/s) / 7.5 x 10^12 Hz)
you can do the math
I am assuming u that 108 is 10^8 and the 1012 is 10^12
3 0
4 years ago
33. Hydrocarbons that release pleasant odors are called_________<br> hydrocarbons. (1 point)
olya-2409 [2.1K]

Answer:

Aromatic Hydrocarbons

Explanation:

Aromatic (Pleasant Odour) Hydrocarbons are those having pleasant odours.

8 0
3 years ago
Read 2 more answers
What is the empirical formula for a compound that contains 79.86 % iodine and 20.14 % oxygen by mass?
serg [7]

Answer:

IO₂

Explanation:

We have been given the mass percentages of the elements that makes up the compound:

Mass percentage given are:

Iodine = 79.86%

Oxygen = 20.14%

To calculate the empirical formula which is the simplest formula of the compound, we follow these steps:

> Express the mass percentages as the mass of the elements of the compound.

> Find the number of moles by dividing through by the atomic masses

> Divide by the smallest and either approximate to nearest whole number or multiply through by a factor.

> The ratio is the empirical formula of the compound.

Solution:

I O

% of elements 79.86 20.14

Mass (in g) 79.86 20.14

Moles(divide by

Atomic mass) 79.86/127 20.14/16

Moles 0.634 1.259

Dividing by

Smallest 0.634/0.634 1.259/0.634

1 2

The empirical formula is IO₂

7 0
3 years ago
Lithium iodide has a lattice energy of -7.3 x 102(kj/mol) and a heat of hydration of -793 kj/mol. find the heat of solution for
marishachu [46]

Given molecule Lithium iodide (LiI)

Heat of hydration = -793 kj/mol

Lattice energy = -730 kJ/mol

Heat of hydration = Heat of solution - Lattice energy

Heat of solution = Hydration + Lattice = -793 + (- 730) = -1523 kJ/mol

Now,

Mass of LiI = 15.0 g

molar mass of LiI = 134 g/mol

# moles of LiI = 15/134 = 0.112 moles

Heat of solution for 1 mole of LiI = -1523 KJ

Therefore, for 0.112 moles of LiI the corresponding heat is

= 0.112 *(-1532) = 171.6 kJ

5 0
3 years ago
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