Total internal energy change is equals to -44.83kJ
Q=-73.2kJ (negative sign indicates that heat was released by the system),
P= 50.0atm
ΔU= Q + W, FIRST LAW OF THERMODYNAMICS..........(1)
ΔV= Final volume - initial volume= 2.00 litre - 7.60litre= -5.60litre
work done by the system (w)= -PΔV
w= -(50.0×(-5.60)) atm×litre= 280atm litre
1 atm litre= 101.325J
w= 280 ×101.325 J= 28,371J
1kJ=1000J,
w=28.37KJ,
so putting in the values in equation (1)...
energy change(ΔU) = -73.2 kJ + 28.37 kJ
= - 44.83 kJ
The question is incomplete, complete question is ;
While idly tossing some keys from hand to hand one day, your friend Reuben (an expert chemist) says this: "Soluble metal oxides form hydroxides when dissolved in water." Using Reuben's statement, and what you already know about chemistry, predict the products of the following reaction. Be sure your chemical equation is balanced.
Answer:
The product will be potassium hydroxide.
Explanation:
When aqueous potassium oxide reacts with water it gives aqueous solution of potassium hydroxide as a product. And potassium hydroxide is a hydroxide of potassium metal with formula KOH.
According to recation , 1 mole of potassium oxide when recats with 1 mole of water to give 2 moles of potassium hydroxide.
N
Y
N
N
N
Y
These are the answers
Answer:
I believe it's qualitative and continuous.
Explanation: