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Masteriza [31]
3 years ago
11

How many molecules in 8H2(g)+4O2

Chemistry
1 answer:
vlada-n [284]3 years ago
7 0
The answer to your question is 16grams
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CAN SOMEONE HELP ME ON THIS PLEASE
lord [1]

<em>option C gas.............................. ᕕ( ᐛ )ᕗ</em>

6 0
3 years ago
You conduct an experiment that requires the creation of an ammonia solution. You do this by reacting 50.0 L of nitrogen gas with
ozzi

Answer : The molarity of the resulting ammonia solution is, 0.89 M

Explanation :

The balanced chemical reaction is:

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

First we have to calculate the moles of nitrogen gas.

As we know that at STP, 1 mole of gas occupies 22.4 L volume of gas.

As, 22.4 L volume of nitrogen gas present in 1 moles of nitrogen gas

So, 50.0 L volume of nitrogen gas present in \frac{50.0}{22.4}=2.23 moles of nitrogen gas

Thus, the moles of nitrogen gas is 2.23 moles.

Now we have to calculate the moles of ammonia gas.

From the reaction, we conclude that

As, 1 mole of N_2 react to give 2 mole of NH_3

So, 2.23 moles of N_2 react to give 2.23\times 2=4.46 moles of NH_3

Now we have to calculate the molarity of the resulting ammonia solution.

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Moles of ammonia}}{\text{Volume of solution (in L)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{4.46mole}{5.0L}

\text{Molarity}=0.89M

Therefore, the molarity of the resulting ammonia solution is, 0.89 M

7 0
3 years ago
How do I solve for V1 in this equation ​
arlik [135]

Answer:

<h2>V_{1} = \frac{P_{2}V_{2}T_{1}}{P_{1}T_{2}}</h2>

Explanation:

\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

<u>First of all cross multiply</u>

That's

P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}

<u>Next divide both sides by </u>P_{1}T_{2}<u>  in order to isolate </u>V_{1}

We have

\frac{P_{1}V_{1}T_{2}}{P_{1}T_{2}} = \frac{P_{2}V_{2}T_{1}}{P_{1}T_{2}}

We have the final answer as

V_{1} = \frac{P_{2}V_{2}T_{1}}{P_{1}T_{2}}

Hope this helps you

3 0
4 years ago
A common demonstration in chemistry courses involves adding a tiny speck of manganese(IV) oxide to a concentrated hydrogen perox
Nuetrik [128]

Answer:

2H_{2}O_{2} ---> 2H_{2}O + O_{2}

2,2,1 being the coefficients

Explanation:

These type of question rely on the person answering the question knowing the formula of hydrogen peroxide. Hydrogen peroxide has a formula that is very similar to that of water except it has a two after the O, which makes it very easy to remember.

6 0
4 years ago
Calculate the number of atoms in 6.5 moles of NaCI
Ne4ueva [31]

Answer:

1 \: mole = 6.02 \times  {10}^{23}  \: atoms \\ 6.5 \: moles = (6.5 \times  {6.02 \times 10}^{23} ) \: atoms \\  = 3.913 \times  {10}^{24}  \: atoms

5 0
3 years ago
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