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Masteriza [31]
2 years ago
11

How many molecules in 8H2(g)+4O2

Chemistry
1 answer:
vlada-n [284]2 years ago
7 0
The answer to your question is 16grams
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What is the correct orbital diagram for carbon
Viefleur [7K]
This is a basic orbital diagram for carbon

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2 years ago
What is the difference between Arrhenius acids-base and bronsted-lowry acids bases? Justify your answer.
Oxana [17]

Answer:

A Bronsted-Lowry acid like and Arrhenius acid is a compound that breaks down to give an H+ in solution. The only difference is that the solution does not have to be water. ... An Arrhenius base is a molecule that when dissolved in water will break down to yield an OH- or hydroxide in solution.

Explanation:

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2 years ago
Which two human activities are believed to be the greatest contributors to global warming?
vivado [14]
B. Deforestation and burning of fossil fuels. <span />
7 0
3 years ago
Read 2 more answers
Physical Meaning of pKa Which of the following aqueous solutions has the lowest pH: 0.1 M HCl; 0.1 M acetic acid (pKa = 4.86); 0
ser-zykov [4K]

Answer:

<em>The solution with the lowest pH is 0.1 M HCl.</em>

Explanation:

Since the three solutions have the same concentration (0,1M) it is only necessary to look at the pKa of each solution.

Also, knowing that a higher pKa means a lower Ka, because pKa = -Log (Ka). Thus, a lower Ka means a lower concentration of protons with a higher pH ( pH = -Log [H+].

The HCl doesn't have a pKa because is a strong acid that dissociates completely. Therefore, this solution produces a lower pH. Looking at the pKa of acetic acid and formic acid solutions, the second with the lowest pH is the formic acid solutions and the higher pH is for the acetic acid solution.

3 0
3 years ago
Find the potentials of the following electrochemical cell:
melomori [17]

Answer: 0.18 V

Explanation:-

Cd/Cd^{2+}(0.10M)//Ni^{2+}(0.50M)?Ni

Here Cd undergoes oxidation by loss of electrons, thus act as anode. nickel undergoes reduction by gain of electrons and thus act as cathode.

E^0_(Cd^{2+}/Cd)=-0.40V[/tex]

E^0_(Ni^{2+}/Ni)=-0.24V[/tex]

Cd+Ni^{2+}\rightarrow Cd^{2+}+Ni

Here Cd undergoes oxidation by loss of electrons, thus act as anode. nickel undergoes reduction by gain of electrons and thus act as cathode.

E^0=E^0_{cathode}- E^0_{anode}

Where both E^0 are standard reduction potentials.

E^0=E^0_{[Ni^{2+}/Ni]}- E^0_{[Cd^{2+}/Cd]}

E^0=-0.24-(-0.40)=0.16V

Using Nernst equation :

E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Cd^{2+}]}{[Ni^{2+]}

where,

n = number of electrons in oxidation-reduction reaction = 2

E^o_{cell} = standard electrode potential = 0.16 V

E_{cell}=0.16-\frac{0.0592}{2}\log \frac{[0.10]}{[0.5]}

E_{cell}=0.18V

Thus the potential of the following electrochemical cell is 0.18 V.

6 0
2 years ago
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