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stich3 [128]
3 years ago
10

Hydrogen bombs and stars both produce energy with nuclear _____.

Physics
1 answer:
Kruka [31]3 years ago
3 0

Answer;

- Nuclear fusion

Explanation;

-Hydrogen bombs and stars both produce energy with the nuclear fusion. On other side, the Sun and other stars make heat and light by nuclear reactions.

-The first stage of a hydrogen bomb involves a fission explosion which in turn leads to a nuclear fusion. The extreme heat and pressure from the initial atomic blast force together deuterium and tritium (two light gases made of hydrogen). When they are forced together, some of the hydrogen atoms fuse to one another, creating helium.

-This process of fusion releases even more energy per unit of mass than fission does, and the energy released from the fusion reaction also feeds back into the fission reaction, increasing its output.

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Answer:

P₂ = 1.22 kPa

Explanation:

This problem can be solved using the equation of state:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

where,

P₁ = initial pressure = 1 KPa

P₂ = final pressure = ?

V₁ = initial Volume = 1 liter

V₂ = final volume = 1.1 liter

T₁ = initial temperature = 290 k

T₂ = final temperature = 390 k

Therefore,

\frac{(1\ kPa)(1\ liter)}{290\ k} =\frac{(P_2)(1.1\ liter)}{390\ k}\\\\P_2= \frac{(1\ kPa)(1\ liter)(390\ k)}{(290\ k)(1.1\ liter)}

<u>P₂ = 1.22 kPa</u>

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3 years ago
Radioactive was discovered by Albert Einstein <br><br> Truth or False <br><br> Need answer
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False .......................
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attashe74 [19]

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Two parallel square metal plates that are 1.6 cm apart and 24 cm on each side carry equal but opposite charges uniformly spread
Fiesta28 [93]

The amount of extra electrons present on the negative surface is

57.2 x 10^{10}.

Distance =1.6 cm

Side = 24 cm

Electric field = 18000 N/C

Calculating the capacitance in the metal plates is necessary.

Using the capacitance formula

C=\frac{e_{0}A }{d}

Putting the value

C = 8.85 x 10^{-12}x (24 x 10^{-2})^{2}/1.6 x 10^{-2}

C = 0.318 x 10^{-10} F

<h3>Calculation of potential</h3>

V = Ed

V = 18000 x 1.6 x 10^{-2} V

V = 288 V

<h3>Calculation of charge</h3>

Q = CV

Q = 0.318 x 10^{-10} x 288

Q = 91.54 x 10^{-10} C

Charge on the both the plates

Q = +91.54 x 10^{-10}

Q = - 91.54 x 10^{-10}

Calculation of excess electrons on the negative surface:

n = q/e

n = 91.54 x 10^{-10}/ 1.6 x 10^{-19}

n = 57.2 x 10^{10} electrons

Hence, the number of excess electrons on the negative surface is

57.2 x 10^{10}.

Learn more about capacitance here:

brainly.com/question/14746225

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What is inside of a blackhole ?
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