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kozerog [31]
3 years ago
9

Which statement is most likely true?

Physics
1 answer:
Bumek [7]3 years ago
3 0
Subduction occurs in both locations
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What is 0.94kg divided by 2.4n
LuckyWell [14K]

Answer:

0.39166666666

Explanation:

7 0
3 years ago
What two models are used to describe how light behaves
S_A_V [24]

Answer:

Light is one of nature's ways of moving energy from one place to another.

Explanation:

It has no substance, or mass. How does light travel? Light behaves like a traveling wave, something like waves in a string or on the surface of water.

5 0
2 years ago
A motorcycle starts to move from rest. If the velocity of the motorcycle becomes 90 km/hr
bagirrra123 [75]

Explanation:

90 kmhr—1 x 1000/3600 = 25ms—1

U = 0 ms—1

V = 25ms—1

t = 10 s

a = ?

a = V - U/t

a = 25 - 0/10

a = 25/10

a = 2.5 ms—1

6 0
2 years ago
An object is dropped from a height h. during the final second of its fall, it traverses a distance of 41.2 m. what was h?
Leya [2.2K]
41.2 = h-1/2g(t-1)^2 
<span> {-h = -1/2gt^2-1/2g+g*t-41.2 
</span><span> {h = 1/2gt^2 
</span><span> summing them up 
</span><span> 0 = -1/2g+g*t-41.2 
</span><span> 41.2 +4.9 = g*t 
</span><span> t = 46.1/9.8 = 4.70 sec 
</span><span> h = 1/2gt^2 =4.9*(4.70^2) = 108.241 m </span>
3 0
3 years ago
Coherent light with wavelength = 600 nm falls on two very narrow closely spaced slits and the interference pattern is observed o
Mrac [35]

Answer:

The distance between the two slits is 1.2mm.    

Explanation:

The physicist Thomas Young establishes, through its double slit experiment, a relationship between the interference (constructive or destructive) of a wave, the separation between the slits, the distance between the two slits to the screen and the wavelength.

\Lambda x = L\frac{\lambda}{d}  (1)

Where \Lambda x is the distance between two adjacent maxima, L is the distance of the screen from the slits, \lambda is the wavelength and d is the separation between the slits.  

If light pass through two slits a diffraction pattern in a screen will be gotten, at which each bright region corresponds to a crest, a dark region to a trough, as consequence of constructive interference and destructive interference in different points of its propagation to the screen.  

Therefore, d can be isolated from equation 1.

d = L\frac{\lambda}{\Lambda x}  (2)

Notice that it is necessary to express L and \lambda in units of millimeters.

L = 4m \cdot \frac{1000mm}{1m} ⇒ 4000mm

\lambda = 600nm \cdot \frac{1mm}{1x10^{6}nm} ⇒ 0.0006mm

d = (4000mm)\frac{0.0006mm}{2mm}

d = 1.2mm

Hence, the distance between the two slits is 1.2mm.

6 0
2 years ago
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