a satellite is traveling in a orbit around the earth. what change would cause it to experience more gravitational force from the
1 answer:
The correct answer is:
<span>A. orbiting closer to the earths surface.
In fact, the gravitational force exerted by the Earth on the satellite is
</span>
<span>where
G is the gravitational constant
M is the Earth mass
m is the satellite mass
r is the distance of the satellite from the Earth's surface
We can see that, if the satellite orbits closer to the Earth's surface, its distance r from the centre of the planet decreases. But when r decreases, F (the gravitational force) increases, so A is the correct answer.</span>
<span>A. orbiting closer to the earths surface.
In fact, the gravitational force exerted by the Earth on the satellite is
</span>
<span>where
G is the gravitational constant
M is the Earth mass
m is the satellite mass
r is the distance of the satellite from the Earth's surface
We can see that, if the satellite orbits closer to the Earth's surface, its distance r from the centre of the planet decreases. But when r decreases, F (the gravitational force) increases, so A is the correct answer.</span>
You might be interested in
Answer:
<em>The object with the twice the area of the other object, will have the larger drag coefficient.</em>
<em></em>
Explanation:
The equation for drag force is given as
where IS the drag force on the object
p = density of the fluid through which the object moves
u = relative velocity of the object through the fluid
p = density of the fluid
= coefficient of drag
A = area of the object
Note that is a dimensionless coefficient related to the object's geometry and taking into account both skin friction and form drag. The most interesting things is that it is dependent on the linear dimension, which means that it will vary directly with the change in diameter of the fluid
The above equation can also be broken down as
∝
A
where is the pressure exerted by the fluid on the area A
Also note that =
which also clarifies that the drag force is approximately proportional to the abject's area.
<em>In this case, the object with the twice the area of the other object, will have the larger drag coefficient.</em>