Answer:
0.74 m/s
Explanation:
given,
time taken by the ramp to cover cliff , t = 64 s
acceleration = 0.37 m/s²
distance traveled by the belt

Clifford is moving with constant acceleration
...(1)
initial velocity is equal to zero
........(2)
equating equation (1) and (2)





Speed of the belt is equal to 0.74 m/s
-- Use the formula D=(1/2)·(g)·(t²) to calculate how long
it takes the flower pot to fall to the ground.
1.5 m = (1/2) · (9.8 m/s²) · (t²)
t² = (1.5 m) / (4.9 m/s²)
t = 0.554 second
-- Use the formula Distance = (speed)·(time) to calculate
how far the pot traveled horizontally in that amount of time.
Distance = (8 m/s) · (0.554 sec)
Distance horizontally = 4.43 meters
Answer:
2.98 m/s^2
Explanation:
I have done this before and it was a question on my physics test
0N. The net force acting on this firework is 0.
The key to solve this problem is using the net force formula based on the diagram shown in the image. Fnet = F1 + F2.....Fn.
Based on the free-body diagram, we have:
The force of gases is Fgases = 9,452N
The force of the rocket Frocket = -9452
Then, the net force acting is:
Fnet = Fgases + Frocket
Fnet = 9,452N - 9,452N = 0N