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3 years ago

How are flow of electrons in a conductor and the direction of conventional current related??

Physics

1 answer:

lys-0071 [83]3 years ago

5 0

Answer:

flow of electron is just opposite to the flow for current. Electrons flow from the negative terminal to the positive. Conventional current or simply current, behaves as if positive charge carriers cause current flow. Conventional current flows from the positive terminal to the negative.

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A particle executes simple harmonic motion with an amplitude of 2.00 cm. At what positions does its speed equal one fourth of it

White raven [17]

Answer:

The positions are 0.0194 m and - 0.0194 m.

Explanation:

Given;

amplitude of the simple harmonic motion, A = 2.0 cm = 0.02 m

speed of simple harmonic motion is given as;

$v = \omega \sqrt{A^2-x^2}$

the maximum speed of the simple harmonic motion is given as;

$v_{max} = \omega A$

when the speed equal one fourth of its maximum speed

$v =\frac{v_{max}}{4}$

$\omega\sqrt{A^2-x^2} = \frac{\omega A}{4} \\\\\sqrt{A^2-x^2}= \frac{A}{4}\\\\A^2-x^2 = \frac{A^2}{16} \\\\x^2 = A^2 - \frac{A^2}{16} \\\\x^2 = \frac{16A^2 - A^2}{16} \\\\x^2 = \frac{15A^2}{16} \\\\x= \sqrt{\frac{15A^2}{16} } \\\\x = \sqrt{\frac{15(0.02)^2}{16} }\\\\x = 0.0194 \ m \ \ or\ - 0.0194 \ m$

Thus, the positions are 0.0194 m and - 0.0194 m.

8 0

3 years ago

Consult Interactive Solution 7.10 for a review of problem-solving skills that are involved in this problem. A stream of water st

AlekseyPX

Explanation:

Initial speed of the incident water stream, u = 16 m/s

Final speed of the exiting water stream, v = -16 m/s

The mass of water per second that strikes the blade is 48.0 kg/s.

We need to find the magnitude of the average force exerted on the water by the blade. The force acting on an object is given by :

$F=\dfrac{m(v-u)}{t}$

Here, $\dfrac{m}{t}=48\ kg/s$

$F=48\times (-16-16)\ N\\\\F=-1536\ N\\\\|F|=1536\ N$

So, the magnitude of the average force exerted on the water by the blade is 1536 N.

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3 years ago

Newtons first law stateS that object will move With a constant velocity if nothing acts on it. Does our every day experience con

bazaltina [42]

Answer:

Explanation:

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3 years ago

Why is it difficult to use the law of conservation of energy to calculate the

Liula [17]

Answer:

Inelastic collisions actually do conserve energy, but the loss of energy to heat and mechanical vibration is hard to calculate so the math equating energy before and energy after is hard to balance.

7 0

3 years ago

Read 2 more answers

Two wires, each of length 1.3 m, are stretched between two fixed supports. On wire A there is a second-harmonic standing wave wh

UNO [17]

Answer:

Explanation:

Given

Length of each wire $L=1.3\ m$