All categories

3 years ago

Which of the following could result from the fission of carbon?

1 answer:

3 0

In nuclear reactions, there are can be two kinds: nuclear fission and nuclear fusion. From the word itself, fusion is combination while fission is breaking. Nuclear reactions are different from chemical reactions. Whereas chemical reactions from compounds by exchanging elements, nuclear reactions add or eliminate subparticles, like protons, neutrons and electrons.

So, when carbon is split up, their protons should add up to 6, which is its atomic number. From the choices, the only obvious answer is two lithium atoms. To investigate further, lithium has an atomic number of 3. So, two lithium atoms would equal to 6.

Therefore, the answer is <span>two lithium atoms.</span>

You might be interested in

please help me please

Musya8 [376]

Answer:

Two advantages are: Its cheap and it is a renewable energy source. Two disadvantages are it's not windy everyday and it will take up a lot of space for windmills.

Explanation:

4 0

3 years ago

Diamond is forever" is one of the most successful advertising slogans of all time. but is it true? for the reaction shown below,

Zielflug [23.3K]

The given reaction is

$C _{(Diamond)}\rightarrow C_{(Graphite)}$

An element can exist in 2 or more different forms which have totally different chemical and physical properties. They are known an allotropes.

Diamond and Graphite are allotropic forms of carbon. In the given reaction, diamond is changing to graphite and we have to find out the standard free energy of this reaction. This will help us to find out whether this reaction is spontaneous at 298 K or not.

The following data is needed for calculations which is taken from standard reference table.

$H_{f}^{0}(diamond)= 1.895 kJ/mol$

$H_{f}^{0}(graphite)= 0$

$S^{0}(diamond)=2.337 J/mol-K$

$S^{0}(graphite)=5.740 J/mol-K$

Step 1: Find ΔH⁰ rxn for the given reaction.

The formula to calculate ΔH⁰ rxn is given below.

$\bigtriangleup H^{0}_{rxn}= H_{f}(product)- H_{f}( reactant)$

We have graphite on product side and diamond on reactant side.

Therefore, $\bigtriangleup H^{0}_{rxn}= H_{f}(graphite)- H_{f}(diamond)$

Let us plug in the values given above.

$\bigtriangleup H^{0}_{rxn}= 0 - 1.895 kJ/mol$

$\bigtriangleup H^{0}_{rxn}= - 1.895 kJ/mol$

ΔH⁰ rxn for the given reaction is -1.895 kJ/mol

Step 2 : Find ΔS⁰ rxn for the given reaction.

The formula to calculate ΔS⁰ rxn is

$\bigtriangleup S^{0}_{rxn}= S^{0}(product)- S^{0}( reactant)$

$\bigtriangleup S^{0}_{rxn}= S^{0}(graphite)- S^{0}(diamond)$

$\bigtriangleup S^{0}_{rxn}= (5.740J/mol.K) - (2.337 J/mol.K)$

$\bigtriangleup S^{0}_{rxn}= 3.403 J/mol.K$

Let us convert this to kJ.

$\frac{3.403J}{mol.K}\times \frac{1 kJ}{1000J}= 3.403\times 10^{-3}kJ/mol.K$

ΔS⁰ rxn for the given reaction is 3.403 x 10⁻³ kJ/mol.K

Step 3: Find standard free energy ΔG⁰ rxn.

ΔG⁰ rxn for the given reaction is calculated as

$\bigtriangleup G^{0}_{rxn}= \bigtriangleup H^{0}_{rxn}- T\times \bigtriangleup S^{0}_{rxn}$

We have T = 298 K. Let us plug in the calculated values of ΔH⁰ rxn and ΔS⁰ rxn.

$\bigtriangleup G^{0}_{rxn}= - 1.895 kJ/mol - [(298K)\times 3.403\times 10^{-3}kJ/mol.K]$

$\bigtriangleup G^{0}_{rxn}= - 1.895 kJ/mol - [1.014 kJ/mol]$

$\bigtriangleup G^{0}_{rxn}= - 2.909 kJ/mol$

The standard free energy change for the given reaction is -2.909 kJ/mol

The negative value of delta G⁰ suggests that the given reaction is spontaneous at room temperature. That means diamond will slowly convert to graphite. The speed of this reaction is extremely slow, but yet the reaction is taking place. So over a period of time diamond will become graphite.

Therefore "Diamond is forever" is not true as it is going to get converted to graphite.

7 0

4 years ago

How many moles of KCl are in 2 L of 2.5 M KCl solution?

beks73 [17]

2.5LX2 M=5 moles

As Molarity X Volume= Total Number of Moles

3 0

3 years ago

A sample of helium gas inside a closed but flexible container occupies a volume of 355mL at 23°C. If the pressure is held consta

guapka [62]

Answer:

978.19° C

Explanation:

P1V1/T1 =P2V2/T2 Since the pressure is constant, this can be written as

V1/T1 = V2/T2 RE-ARRANGE TO

V2 * T1/V1 = T2 Note: T must be in Kelvin!!

1.5 L * (273.15 + 23) / (.355 L ) = T2 = 1251.338 K =978.19 C

6 0

2 years ago

Giving one KG equals 2.20 pounds how many kilograms are in 338 pounds

dezoksy [38]

Answer:

154 kg

Explanation:

Step 1: Define conversion

1 kg = 2.20 lbs

Step 2: Use Dimensional Analysis

$338 \hspace{3} lbs(\frac{1 \hspace{3} kg}{2.20 \hspace{3} lbs} )$ = 153.636 kg

Step 3: Simplify

We are give 3 sig figs.

153.636 kg ≈ 154 kg

7 0

4 years ago