Answer:
8.08 × 10⁻⁴
Explanation:
Let's consider the following reaction.
COCl₂(g) ⇄ CO (g) + Cl₂(g)
The initial concentration of phosgene is:
M = 2.00 mol / 1.00 L = 2.00 M
We can find the final concentrations using an ICE chart.
COCl₂(g) ⇄ CO (g) + Cl₂(g)
I 2.00 0 0
C -x +x +x
E 2.00 -x x x
The equilibrium concentration of Cl₂, x, is 0.0398 mol / 1.00 L = 0.0398 M.
The concentrations at equilibrium are:
[COCl₂] = 2.00 -x = 1.96 M
[CO] = [Cl₂] = 0.0398 M
The equilibrium constant (Keq) is:
Keq = [CO].[Cl₂]/[COCl₂]
Keq = (0.0398)²/1.96
Keq = 8.08 × 10⁻⁴
Answer:
Uh first of all this is algebra but I'll answer this
First distribute the three and 5 (Multiply them by both terms inside parenthesis.
3x-6=5x+20
Then add like terms
8x=14
Divide 8 by 8 and 8 by 14
x = 14/8
Explanation:
Explanation:
A strip of solid palladium metal is put into a beaker of nicl2
Palladium (Pd) + Nickel Chloride (NiCl2)
To answer this question properly you must refer to the reactivity series.
The activity series is a chart of metals listed in order of declining relative reactivity. The top metals are more reactive than the metals on the bottom.
In this series, Nickel is higher than Palladium. This means that if a Palladium strip is placed into a solution of a Ni salt, then a reaction will not take place, nothing would happen.
Because Pd is lower than Ni in the reactivity series.
There is no reaction so no equation.
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