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2 years ago

13. Which could be true about an unknown sample with a pH of 7? (2 points)

Chemistry

2 answers:

Rasek [7]2 years ago

7 0

Answer: Option (a) is the correct answer.

Explanation:

Substance which show pH less than 7 are acidic in nature. For example, HCl being a strong acid has pH very less than 7.

Substances which show pH greater than 7 are basic in nature. For example, NaOH being basic in nature has pH greater than 7.

Whereas substances which have pH equal to 7 are neutral in nature, that is, they are neither acidic nor basic.

For example, water is neutral in nature.

Thus, we can conclude that the statement it contains only water is true about an unknown sample with a pH of 7.

laiz [17]2 years ago

5 0

The best and most correct answer among the choices provided by your question is the first choice or letter A.

A ph of 7 contains only water.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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1.) What coefficient values will balance the reaction shown? CH4 + O2 ?CO2 + H2O

Varvara68 [4.7K]

Answer:

It's simpler than most questions :)

Explanation:

1) B

2) B

3) D

4) A

5) A

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3 years ago

The revival of jansenism, which centered on miracles that allegedly happened at the grave of a jansenist priest, is evidence of

lapo4ka [179]

The evidence of the revival of Jansenism is the desire of ordinary people to connect themselves to what they saw as the direct work of God.

<h3>What is Jansenism?</h3>

Jansenism is a theological movement that is done with the mixing of Catholicism. It was active in France's kingdom.

Primarily throughout the seventeenth and eighteenth centuries, Jansenism flourished inside Roman Catholicism before being denounced as heresy in 1653 by Pope Innocent X.

Thus, the yearning of common people to participate in what they perceived as God's direct action is proof of the rebirth of Jansenism.

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1 year ago

A sample 0.100 moles of a gas is collected at at stp. what is the volume of the gas in liters? group of answer choices 2.44 l

bearhunter [10]

n = 0.100 moles

At STP (standard temperature pressure), where gas is collected, the temperature is 0°C and the pressure is 1 atm.

$\\$\therefore$ Temperature $(T)=0^{\circ} \mathrm{C}=0^{\circ}+273$

$=273K$

$Pressure $(P)=1$ atm.$

The ideal gas equation indicates that

$\begin{aligned}& P V=n R T \Rightarrow V=\frac{n R T}{P} \\\therefore & R=\text { gas constant }=0.0821 \mathrm{~L} \cdot \mathrm{cetm} / \mathrm{mo} / \cdot K\end{aligned}$

$\begin{aligned}&V=\frac{0.100 \mathrm{~mol} \cdot \times 0.0821 \mathrm{~L} \cdot \mathrm{atm} / \mathrm{mol} . \mathrm{K} \times 273 \mathrm{~K}}{1 \mathrm{~atm}} \\&V=\frac{2.24 L}{1}\end{aligned}\\$

$V=2.24L$

Group of answer choices $2.44L$ .The volume occupied by mole of a given gas at a given temperature and pressure is expressed as the gas's molar volume.

The most typical illustration is the molar volume of a gas at STP, which is equal to $2.44L$ for $1$ mole of any ideal gas at a temperature of $273.15$ Kand a pressure of $1$ atm.

Hence, the volume of the gas is $2.24L$ .

A unit is stated to have a temperature of absolute zero $(273 Kelvins)$ and an atmospheric pressure of one atmosphere, or $1$ atm, at standard temperature and pressure. Additionally, at STP, a mole of any gas takes up $22.414 L$ of space. Keep in mind that this idea only applies to gases.

For experimental measurements to be established under standard conditions that allow for comparisons between various sets of data, standard temperature and pressure must be met.

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1 year ago

The radioisotope potassium-40 decays to argon-40 by positron emission with a half-life of 1.3 Ã 109 yr. A sample of moon rock wa

Aloiza [94]

Answer:

4.66 x 10^8 yr

Explanation:

The age of the rock can be calculated using the equation:

ln (N/N₀) = - kt where N is the quantiy of radioisotope decayed and N₀ is the initially quantity present of the radioisotope; k is the decay constant, and t is the time.

Now from the data , we have 78 argon-40 atoms for every 22 potassium-40 atoms, we can deduce that originally we had 22 + 78 = 100 atoms of potassium-40 so this is our N₀.

When we look at the equation, we see that k is unknown, but we can calculate it from the half-life which is given by the equation:

k = 0.693/ t half-life = 0.693/ 1.3 x 10⁹ yr = 5.33 x 10⁻¹⁰ yr⁻¹

Now we are in position to answer the question.

ln ( 78/100 ) = - (5.33 x 10⁻¹⁰ yr⁻¹ ) t

- 0.249 = - 5.33 x 10⁻¹⁰ yr⁻¹ t

0.249/ 5.33 x 10⁻¹⁰ yr⁻¹ = t

4.66 x 10^8 yr

8 0

3 years ago

What is the purpose of the solvent in chromatography?

prisoha [69]

Solid substances cannot raise to the top of the ‘card’. They need to be in liquid form.

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2 years ago