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AnnZ [28]
3 years ago
10

13. Which could be true about an unknown sample with a pH of 7? (2 points)

Chemistry
2 answers:
Rasek [7]3 years ago
7 0

Answer: Option (a) is the correct answer.

Explanation:

Substance which show pH less than 7 are acidic in nature. For example, HCl being a strong acid has pH very less than 7.

Substances which show pH greater than 7 are basic in nature. For example, NaOH being basic in nature has pH greater than 7.

Whereas substances which have pH equal to 7 are neutral in nature, that is, they are neither acidic nor basic.

For example, water is neutral in nature.

Thus, we can conclude that the statement it contains only water is true about an unknown sample with a pH of 7.

laiz [17]3 years ago
5 0
The best and most correct answer among the choices provided by your question is the first choice or letter A.

A ph of 7 contains only water.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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A ------------ ----------------- is the dying out of a large number of species on a global scale
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Answer:

Extinction event or sometimes known as Mass extinction

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These events typically are typically widespread and rapid decrease in the biodiversity (which takes into account spread and existence of current species). The worst mass extinction was Permian–Triassic extinction where over 90% of species of organisms vanished.

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Which metal in Period 5 is very reactive and has two valence electrons in each atom?
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How do the cells in your body get energy?
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Adenosine triphosphate is the:
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C. Cellular respiration
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Given the following equilibrium constants: Kb B(aq) + H2O(l) ⇌ HB+(aq) + OH−(aq) 1/Kw H+(aq) + OH−(aq) ⇌ H2O(l) What is the equi
bija089 [108]

<u>Answer:</u> The value of K_c for the net reaction is \frac{K_b}{K_w}

<u>Explanation:</u>

The given chemical equations follows:

<u>Equation 1:</u>  B(aq.)+H_2O(l)\rightleftharpoons HB^+(aq.)+OH^-(aq.);K_b

<u>Equation 2:</u>  H^+(aq.)+OH^-(aq.)\rightleftharpoons H_2O(l);\frac{1}{K_w}

The net equation follows:

B(aq.)+H^+(aq.)\rightleftharpoons HB^+(aq.);K_c

As, the net reaction is the result of the addition of first equation and the second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the second equilibrium constant.

The value of equilibrium constant for net reaction is:

K_c=K_1\times K_2

We are given:  

K_1=K_b

K_2=\frac{1}{K_w}

Putting values in above equation, we get:

K_c=K_b\times \frac{1}{K_w}=\frac{K_b}{K_w}

Hence, the value of K_c for the net reaction is \frac{K_b}{K_w}

7 0
3 years ago
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