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aleksklad [387]
3 years ago
8

What is the empirical formula for a compound that is 43.6% phosphorus

Chemistry
1 answer:
Kazeer [188]3 years ago
3 0

Answer:

d.   P2O5.

Explanation:

We find the ratio of the atoms by dividing the percentages by the relative atomic masses:

P :  43.6 / 30.974 = 1.4076

O:  56.4 / 15.999 =  3.5252

1.4076 : 3.5252

= 1 : 2.5

= 2:5.

So the answer is P2O5.

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You need 5.0 grams of LiOH for a reaction, but all you have on hand is a 2.75 M aqueous LiOH solution. What volume of the soluti
Natalka [10]

Answer:

75.9mL of 2.75M LiOH solution

Explanation:

Molarity is an unit of concentration defined as the ratio between moles and liters. And the molar mass of LiOH is 23.95g/mol. With this information, it is possible to know the volume of solution you should add to supply 5.0g, thus:

5.0g LiOH × (1mol / 23,95g) × (1L / 2.75mol) × (1000mL / 1L) = <em>75.9mL of 2.75M LiOH solution</em>

<em />

I hope it helps!

5 0
3 years ago
ΑC2H6O+βO2 → γC2H4O2+δH2O
olga2289 [7]
Balancing the equation, we get:

2C₂H₆O + O₂ → 2C₂H₄O₂ + 2H₂O

So 
α = 2
β = 1
γ = 2
δ = 2
4 0
3 years ago
Use the table to compare the solubility of substances. Check all of the boxes that apply.
vladimir2022 [97]
<h2>Answers to the rest of the assignment:</h2>

**Check for proof photos at the bottom.**

<h2>_____________________________________</h2>

Use the table to compare the solubilities of substances. Check all of the boxes that apply.

A. Aspirin is less soluble than table salt, but more soluble than carbon dioxide.

C. A saturated solution of table sugar is more concentrated than a saturated solution of table salt.

<h2>_____________________________________</h2>

The solubility of glucose at 30°C is  125 g/100 g water. Classify a solution made by adding 550 g of glucose to 400 mL of water at 30°C. Explain your classification, and describe how you could increase the amount of glucose in the solution without adding more glucose.

Answer: The solution is saturated. At 30°C, 500 g of glucose will dissolve in 400 mL of solution. Of the 550 g glucose added, only 500 g will dissolve and 50 g will precipitate out. The amount of glucose in the solution can be increased by heating the solution because the solubility of solids tends to increase with temperature.

<h2>_____________________________________</h2>

Use the graph to identify the number, letter, or word that completes each statement.  

•      The solubility of Solute D  <u>decreases</u>  as temperature increases.

•      The solubility of Solute <u>E</u>  increases the most as temperature increases.

•      The solubility of Solutes C and D is the same at  <u>20</u>°C.

•      As the temperature increases from 0 to 100, the solubility only changes by about  <u>5</u> grams for Solute B.

<h2>_____________________________________</h2><h2>Explanation:</h2>

In the provided table shows the solubility of 4 different substances. The solubility number for Aspirin is smaller than the number for table salt, but larger than the number for carbon dioxide. Since the solubility if sugar is larger than table salt, its saturated concentration would be higher.

In the given chart, the line representing solubility of solute D decreases as temperature increases. The line for solute E increases the most. At 20°C, the lines of C and D are about the same height.

Here are photos of Edge just incase.

5 0
3 years ago
The density of copper is 8.96g/ml. the mass of 7.00ml of copper is
murzikaleks [220]
Density = mass / volume

8.96 = m / 7.00

m = 8.96 x 7.00

m = 62.72 g
8 0
3 years ago
Read 2 more answers
Kc is 1.67 x 10^20 at 25 °C for the formation of iron(III) oxalate complex ion:
Liula [17]

Answer:

n_{C_2O_4^{2-}}=1.59mol C_2O_4^{2-}

Explanation:

Hello there!

In this case, according to the given information and chemical equation, it turns out possible for us to calculate the moles of C2O4^2- by firstly setting up the equilibrium expression:

Kc=\frac{[[Fe(C_2O_4)_3]^{3-}]}{[Fe^{3+}][C_2O_4^{2-}]^3}

However, according to the question, we just need to apply the given 1:3 mole ratio in the chemical reaction, of iron (III) ions to oxalate ions to obtain:

n_{C_2O_4^{2-}}=0.53molFe^{3+}*\frac{3molC_2O_4^{2-}}{1molFe^{3+}}=1.59mol C_2O_4^{2-}

Regards!

7 0
3 years ago
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