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aleksklad [387]
3 years ago
8

What is the empirical formula for a compound that is 43.6% phosphorus

Chemistry
1 answer:
Kazeer [188]3 years ago
3 0

Answer:

d.   P2O5.

Explanation:

We find the ratio of the atoms by dividing the percentages by the relative atomic masses:

P :  43.6 / 30.974 = 1.4076

O:  56.4 / 15.999 =  3.5252

1.4076 : 3.5252

= 1 : 2.5

= 2:5.

So the answer is P2O5.

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