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3 years ago

Please help!! I have 10 minutes left!!

Chemistry

1 answer:

Licemer1 [7]3 years ago

8 0

Explanation:

1 is a process that occurs when gases in earth's atmosphere trap the sun's heat .

2 . heat in the atmosphere to warm the planet .

I only know the first too sorry ✨

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C6H12O6 is the formula for a sugar molecule.molecules are classified as?

expeople1 [14]

Answer:

D-Glucose

Explanation:

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2 years ago

Blue colour of cupric nitrate on strongly heating gives gives black cupric oxide powder along with oxygen gas and nitrogen dioxi

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Please see the image.

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3 years ago

A copper cylinder, 12.0 cm in radius, is 44.0 cm long. If the density of commoner is 8.90 g/cm3, calculate the mass in grams of

inna [77]

The mass of the copper cylinder is 177065.856g

Given:

Radius of the copper cylinder R=12cm

Height of the copper cylinder H=44cm

Density of the cylinder=8.90 $\frac{g}{c m^{3}}$

To find:

Mass of the copper cylinder

Step by Step by explanation:

Solution:

According to the formula, Mass can be calculated as

$\rho=\frac{m}{v}$ and from this

$m=\rho \times v$

Where, m=mass of the cylinder

$\rho$ =density of the cylinder

v=volume of the cylinder

And also cylinder is provided with radius and height value.

So volume of the cylinder is calculated as

$v=\pi r^{2} h$

Where $\pi$ =3.14

r=radius of the cylinder=12cm

h=height of the cylinder=44cm

Thus, $v=3.14 \times 12^{2} \times 44$

v=3.14 \times 144 \times 44

$v=19895.04 \mathrm{cm}^{3}$

And we know that, $m=\rho \times v$

Substitute the known values in the above equation we get

$m=8.90 \times 19895.04$

m=177065.856g or 177.065kg

Result:

Thus the mass of the copper cylinder is 177065.856g

4 0

3 years ago

What is the net force on this box? A.) 0 B.) 45 C.)25 D.)90

Degger [83]

Answer:

Explanation:

Hopefully this helps you!

3 0

2 years ago

Read 2 more answers

What is the concentration of a potassium iodate solution after you complete the following porcedure? Pipette 10 mL of a 0.31 M p

zubka84 [21]

Given:

Initial concentration of potassium iodate (KIO3) M1 = 0.31 M

Initial volume of KIO3 (stock solution) V1 = 10 ml

Final volume of KIO3 V2 = 100 ml

To determine:

The final concentration of KIO3 i.e. M2

Explanation:

Use the relation-

M1V1 = M2V2

M2 = M1V1/V2 = 0.31 M * 10 ml/100 ml = 0.031 M

Ans: The concentration of KIO3 after dilution is 0.031 M

4 0

2 years ago