I had this same question a while back, so I may not be right, but I'm pretty sure it's D. None of the above.
CO2 ~ 1 atom
N202 ~ 4 atom
CO ~ 2 atom
H2OS ~ 3 atom
B
Answer:
517.3 K
Explanation:
Initial volume of gas V1= 114 L
Initial temp. T1= 273 K
Final volume V2= 216 L
Final temp. T2= ?
From Charles law, Volume is directly proportional to temperature provided pressure is kept constant
V1/T1 = V2/T2
T2 = V2T1/V1
T2 = (216×273)/114
T2 = 517.3 K
Mass of KNO₃ : = 40.643 g
<h3>Further explanation</h3>
Given
28.5 g of K₃PO₄
Required
Mass of KNO₃
Solution
Reaction(Balanced equation) :
2K₃PO₄ + 3 Ca(NO₃)₂ = Ca₃(PO₄)₂ + 6 KNO₃
mol K₃PO₄(MW=212,27 g/mol) :
= mass : MW
= 28.5 : 212,27 g/mol
= 0.134
Mol ratio of K₃PO₄ : KNO₃ = 2 : 6, so mol KNO₃ :
= 6/2 x mol K₃PO₄
= 6/2 x 0.134
= 0.402
Mass of KNO₃ :
= mol x MW KNO₃
= 0.402 x 101,1032 g/mol
= 40.643 g