Answer:
22.86% probability that the persons IQ is between 110 and 130
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
If one person is randomly selected what is the probability that the persons IQ is between 110 and 130
This is the pvalue of Z when X = 130 subtracted by the pvalue of Z when X = 110.
X = 130
has a pvalue of 0.9772
X = 110
has a pvalue of 0.7486
0.9772 - 0.7486 = 0.2286
22.86% probability that the persons IQ is between 110 and 130
Step-by-step explanation:
As ANC are collinear,
AB+BC=AC
so,
18+BC = 41
BC = 41-18
BC = 23 is the answer.
Answer:
a = 55/6
Step-by-step explanation:
<u>Solving in steps:</u>
- 3/5a = 5 1/2
- 3/5a = 11/2
- a = 11/2 : 3/5
- a = 11/2*5/3
- a = 55/6 or 9 1/6
To get the value of DK we use proportionality:
AK/EK=BK/KD
thus plugging the values we get:
14/17=7/KD
getting the reciprocal of getting both sides we have:
17/14=KD/7
thus
KD=17/14×7
KD=8.5
thus