Explanation:
<em>Are</em><em> </em><em>the</em><em> </em><em>compounds</em><em> </em><em>formed</em><em> </em><em>by</em><em> </em><em>the</em><em> </em><em>ionic</em><em> </em><em>bonding</em><em> </em><em>or</em><em> </em><em>electronic</em><em> </em><em>bonding</em><em>.</em><em> </em><em>They</em><em> </em><em>are</em><em> </em><em>formed</em><em> </em><em>by</em><em> </em><em>transferring</em><em> </em><em>the</em><em> </em><em>electron</em><em> </em><em>form</em><em> </em><em>one</em><em> </em><em>element's</em><em> </em><em>valance</em><em> </em><em>shell</em><em> </em><em>to</em><em> </em><em>other</em><em> </em><em>element's</em><em> </em><em>shell</em><em>.</em>
<em><u>i</u></em><em><u> </u></em><em><u>hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
4.25 m/s
Explanation:
Force, F = 22 N
Time, t = 0.029 s
mass, m = 0.15 kg
initial velocity of the cue ball, u = 0
Let v be the final velocity of the cue ball.
Use newton's second law
Force = rate of change on momentum
F = m (v - u) / t
22 = 0.15 ( v - 0) / 0.029
v = 4.25 m/s
Thus, the velocity of cue ball after being struck is 4.25 m/s.
Potential Energy = mgh,
where m = mass in kg, g ≈ 10 m/s², h = height above ground = 8 m
PE = mgh
= 70*10*8 = 5600 J
The work is equal to the product between the force applied and the distance covered by the box:

In our problem, W=556 J, and d=1.3 m (the box is lifted to a height of 1.3 m, so it covered 1.3 m from its initial point). Therefore we can find the force applied to lift the box:
Answer:
proper time taken by the person is 9.911 × 10⁻⁵ s
Explanation:
speed of the person in x- direction = 40,000 km/s
= 40,000 × 10³ m/s
= 4 × 10⁷ m/s
when the person just passes the street lamp is switched on which is at x =4 km
Lorentz factor = 
= 
= 1.009
time taken in your frame of reference,t =
=
proper time =
hence, proper time taken by the person is 9.911 × 10⁻⁵ s