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goldfiish [28.3K]
3 years ago
6

Isaac Newton developed the Universal Law of ____________________.

Physics
2 answers:
olganol [36]3 years ago
8 0

Answer:

The three laws of motion

Explanation:

Besides his work on universal gravitation (gravity), Newton developed the three laws of motion which form the basic principles of modern physics. His discovery of calculus led the way to more powerful methods of solving mathematical problems.

alekssr [168]3 years ago
6 0

Answer:

He also formulated his law of Universal Gravitation in the Principia, which states that every point mass attracts every single other point mass by a force pointing along the line intersecting both point.

Explanation:

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Ionic compounds _____.
aleksandr82 [10.1K]

Explanation:

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6 0
3 years ago
A cue stick hits a cue ball with an average force of 22 N for a duration of 0.029 s. If the mass of the ball is 0.15 kg, how fas
Likurg_2 [28]

Answer:

4.25 m/s

Explanation:

Force, F = 22 N

Time, t = 0.029 s

mass, m = 0.15 kg

initial velocity of the cue ball, u = 0

Let v be the final velocity of the cue ball.

Use newton's second law

Force = rate of change on momentum

F = m (v - u) / t

22 = 0.15 ( v - 0) / 0.029

v = 4.25 m/s

Thus, the velocity of cue ball after being struck is 4.25 m/s.

8 0
3 years ago
Read 2 more answers
a object with a mass of 70 kilograms is supported at a height 8 meters above the ground.what's the potential energy of the objec
Agata [3.3K]
Potential Energy = mgh,

where m = mass in kg,  g ≈ 10 m/s², h = height above ground = 8 m

PE = mgh
  
      = 70*10*8 = 5600 J

7 0
3 years ago
You perform 556 J of work lifting a box to a height of 1.3m. How much force did you use to lift the box?
babunello [35]
The work is equal to the product between the force applied and the distance covered by the box:
W=Fd
In our problem, W=556 J, and d=1.3 m (the box is lifted to a height of 1.3 m, so it covered 1.3 m from its initial point). Therefore we can find the force applied to lift the box:
F= \frac{W}{d}= \frac{556 J}{1.3 m}=427.7 N
4 0
3 years ago
Read 2 more answers
In your frame, a person is moving in the positive x-direction at a speed of 40,000 km / s. Suppose that a streetlamp located at
nexus9112 [7]

Answer:

proper time taken by the person is 9.911 × 10⁻⁵ s

Explanation:

speed of the person  in x- direction = 40,000 km/s

                                                           =  40,000 × 10³ m/s

                                                           =  4 × 10⁷ m/s

when the person just passes the street lamp is switched on which is at x =4 km

Lorentz factor = \gamma = \dfrac{1}{\sqrt{1-\dfrac{r^2}{c^2}}}

                                         = \dfrac{1}{\sqrt{1-\dfrac{(4 \times 10^7)^2}{(3 \times 10^8)2}}}

                                         = 1.009

time taken in your frame of reference,t =\dfrac{D}{v}

                                                                 =\dfrac{4}{40000} = 10 ^{-4}s

proper time  =t_0 = \dfrac{t}{\gamma}=\dfrac{10^{-4}}{1.009}= 9.911 \times 10^{-5} s

hence, proper time taken by the person is 9.911 × 10⁻⁵ s

5 0
3 years ago
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