There is no definite end to earths atmosphere, but technically the border between the outer space and earth gets thinner as you move up from the earths surface. The Karman line is the closest definition there is which describes the end of the earth's atmosphere, it is 100 km above earth's sea level at approximately 1.56 % of total earth's radius. This describes the boundary between the outer space and the atmosphere.
Left and right to a point called ad focal point after passing through convex lens
Answer:
The magnitude of the magnetic field is 
Explanation:
From the question we are told that
The mass of the rod is 
The distance of separation is 
The current is
The coefficient of friction is 
Generally for the rod the rod to continue moving at a constant speed
The frictional force must equal to the magnetic field force so

Where 
and 

=> 
substituting values


Answer:
Velocity of the electron mid way = v = 6.47×10⁶ m/s
Explanation:
Electric potential varies with distance as 
At a distance 5 mm , the constant C is evaluated.
C = 
= 
= 3.50×10⁵
Now at the mid point, x = 2.5 mm = 0.0025 m
Potential = V' = 
= 
= 119 V
Kinetic energy per unit charge is equal to the electric potential.
or 0.5 m v^2 = V' q
Here m is the mass of the electron and q is the charge of the electron.
m= 9.1×10⁻³¹ kg
q = 1.6×10⁻¹⁹ coulombs
⇒ 
⇒ 
⇒ v = 6.47×10⁶ m/s
⇒ Velocity of the electron mid way = v = 6.47×10⁶ m/s
Answer:
83.55 μm
Explanation:
In a single slit experiment, the distance (on the screen), y, between the central maximum and the minimum of order, m, is given as:
y =
* λ
where λ = wavelength
a = width of slit
d = distance between slit and screen
To get the width of the slit, we make a the subject of formula:
a = (mλd)/y

(All units of length are in meters)

a = 83.55 μm