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neonofarm [45]
3 years ago
8

Which kinds of objects emit visible light in the electromagnetic spectrum?1)all objects2)radioactive objects3)relatively cold ob

jects4)relatively hot objects
Physics
1 answer:
Lostsunrise [7]3 years ago
8 0
Relatively hot objects emit visible light.
Some examples: 
==> the wire coils in the toaster; 
==> the spoon that you stuck in the flame on the stove;
==> the fine wire in the lightbulb when current goes through it.

VERY radioactive objects also do that.  But if you're actually
standing there watching an object that's THAT radioactive,
then you're in big trouble.
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Please help!!!! on both of them this is physics not math
Lera25 [3.4K]
Ok this is probably the easiest part in physics so lol dont panic. now the way you round is by looking at the exponent which in this case for the first one is -9 so 6.8 is gonna be 0000000068. because when you have a negative exponent you move the decimal to the west side. when you have a positive decimal you move to the east side. I will not do the second one because its best if you try to solve it so you can learn it. good luck my friend.
3 0
3 years ago
Which is an example of an exothermic process?
4vir4ik [10]

Answer:

i think answer is c

Explanation:

as formation water from steam condensed release heat

else all need heat

5 0
3 years ago
. An object has a position given by ~r(t) = [3.0 m − (4.00 m/s)t]ˆı + [6.0 m − (8.00 m/s2 )t 2 ]ˆ , where all quantities are in
kupik [55]

Answer:

(c) 16 m/s²

Explanation:

The position is r(t) = [3.0 \text{ m} - (4.00 \text{ m/s})t]\hat{i} + [6.0 \text{m} - (8.00 \text{ m/s}^2 )t^2 ]\hat{j}.

The velocity is the first time-derivative of <em>r(t).</em>

<em />v(t) = \dfrac{d}{dt}r(t) = -4.00\,\hat{i} -16t\,\hat{j}<em />

The acceleration is the first time-derivative of the velocity.

a(t) = \dfrac{d}{dt} v(t) = -16\hat{j}

Since <em>a(t)</em> does not have the variable <em>t</em>, it is constant. Hence, at any time,

a = -16\hat{j}

Its magnitude is 16 m/s².

4 0
3 years ago
An airplane takes off a runway at a constant speed of 49m/s at constant angle 30 to the horizontal
joja [24]

Complete Question

An airplane takes off a runway at a constant speed of 49 m/s at constant angle 30 to the horizontal.How high (in meters )  is the airplane above the ground 13 seconds after takeoff?

Answer:

The height  is H  =  318.5 \ m

Explanation:

From the question we are told that

   The speed at which the plane takes off is  u = 49 \ m/s

      The angle at which it takes off is  \theta  =  30 ^o

        The time taken is t =  13  s

The vertical distance traveled is  mathematically represented as

          H  =  u sin  \theta  t

Substituting values  

         H  =  (49) * sin (30) *13

        H  =  318.5 \ m

6 0
3 years ago
This important factor of survival for the coral reef is
inna [77]

Answer: biotic

Explanation:

6 0
3 years ago
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