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Firdavs [7]
3 years ago
7

The supporting force exerted by a fluid on an object immersed in it is called ______.

Physics
2 answers:
aniked [119]3 years ago
7 0

Answer: buoyant force

Explanation:

Leokris [45]3 years ago
4 0

Answer:

buoyant force

Explanation:

The buoyant force is the pressure that is exerted on a immersed object by the surrounding fluid.  

The buoyant force acts on the surface of the solid object even if the object is immersed in the fluid partially or completely. If the object is immersed in a fluid, the net force is given by the formula:

F_{bottom}  = (P_{atm} + \rho gh) A

where Patm is the atmospheric pressure at the top of the object

pgh = pressure of the part  in the fluid

F(bottom) is the upward force on the object

The net force is the same as the wight of the displaced object.

The principle is known as the Archimedes principle as the buoyant force is equals the weight of the fluid displaced by the object.  

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Silicon (chemical symbol Si) is located in Group 14, Period 3. Which is silicon
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The law of conservation of momentum states that the total momentum of interacting objects does not _____. This means the total m
drek231 [11]

Answer:

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3 years ago
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If a car moves with a uniform speed of 2m/s in a circle of radius 0.4m, what is its angular speed?
REY [17]

Answer:

The car's angular speed is \frac{rad}{s}.

Explanation:

Angular velocity is usually measured with \frac{radians}{sec}, so I'm going to use that to answer your question.

The relationship between tangential velocity and angular velocity (ω)  is given by:

V = \omega R

Using the values from the question, we get:

2 \frac{m}{s} = \omega (0.4m)

\omega = 5 \frac{rad}{s}

Therefore, the car's angular speed is 5 \frac{rad}{s}.

Hope this helped!

3 0
3 years ago
A speed skater moving across frictionless ice at 9.2 m/s hits a 5.0 m wide patch of rough ice. She slows steadily, then continue
enot [183]

Answer:

a = -5.10 m/s^2

her acceleration on the rough ice is -5.10 m/s^2

Explanation:

The distance travelled on the rough ice is equal to the width of the rough ice.

distance d = 5.0 m

Initial speed u = 9.2 m/s

Final speed v = 5.8 m/s

The time taken to move through the rough ice can be calculated using the equation of motion;

d = 0.5(u+v)t

time t = 2d/(u+v)

Substituting the given values;

t = 2(5)/(9.2+5.8)

t = 2/3 = 0.66667 second

The acceleration is the change in velocity per unit time;

acceleration a = ∆v/t

a = (v-u)/t

Substituting the values;

a = (5.8-9.2)/0.66667

a = -5.099974500127

a = -5.10 m/s^2

her acceleration on the rough ice is -5.10 m/s^2

7 0
3 years ago
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