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Firdavs [7]
2 years ago
7

The supporting force exerted by a fluid on an object immersed in it is called ______.

Physics
2 answers:
aniked [119]2 years ago
7 0

Answer: buoyant force

Explanation:

Leokris [45]2 years ago
4 0

Answer:

buoyant force

Explanation:

The buoyant force is the pressure that is exerted on a immersed object by the surrounding fluid.  

The buoyant force acts on the surface of the solid object even if the object is immersed in the fluid partially or completely. If the object is immersed in a fluid, the net force is given by the formula:

F_{bottom}  = (P_{atm} + \rho gh) A

where Patm is the atmospheric pressure at the top of the object

pgh = pressure of the part  in the fluid

F(bottom) is the upward force on the object

The net force is the same as the wight of the displaced object.

The principle is known as the Archimedes principle as the buoyant force is equals the weight of the fluid displaced by the object.  

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A transformer connected to a 120-V (rms) ac line is to supply 12,500 V (rms) for a neon sign. To reduce shock hazard, a fuse is
Tamiku [17]

Answer:

a) 104

b) 106

c) 884 mA

Explanation:

The ratio of the transformer is given by:

N=\frac{V_{out}}{V_{in}}=\frac{12500V}{120V}=104

We need to know the current in the primary in order to obtain the power applied.

I_1=I_2*N=8.50mA*104=884mA\\\\P=I*V=884*10^{-3}A*120V=106W\\

The current rating of the fuse is the current on the primary, 884mA as we calculated before in order to obtain the power.

4 0
3 years ago
Two converging lenses, one with f = 4.0 cm and the other with f = 37 cm , are made into a telescope. What is the length of this
d1i1m1o1n [39]

Answer:

The length and the magnification of this telescope are 41 cm and 0.108.

Explanation:

Given that,

Focal length of first lens f= 4.0 cm

Focal length of other lens f'= 37 cm

We need to calculate the length of the telescope

Using formula of length

L=f+f'

Put the value into the formula

L=4+37=41 cm

We need to calculate the magnification of the telescope

Using formula of the magnification

m=\dfrac{f}{f'}

Put the value into the formula

m=\dfrac{4}{37}

m=0.108

Hence, The length and the magnification of this telescope are 41 cm and 0.108.

8 0
3 years ago
The reactivity of an atom arises primarily from ___.
kherson [118]

Answer:

E. existence of unpaired electrons in the outermost shell.

Explanation:

7 0
3 years ago
What scientific process would you be using as you identified the characteristics of the buttery
jarptica [38.1K]

Answer:

The butterfly and moth develop through a process called metamorphosis.

Explanation:

hoped i helped

8 0
2 years ago
While riding a chairlift, a 55-kilogram skier is raised a vertical distance of 370 meters. What is the total change in the skier
Lelechka [254]

The change in the skier's gravitational potential energy is 199430 J.

<h3> Gravitational potential energy:</h3>

This is the energy of a body due to its position in a gravitational field. The  S.I unit of gravitational potential energy is Joules (J)

The Change in the skier's gravitational potential energy can be calculated using the formula below.

Formula:

  • ΔP.E = mg(Δh)............... Equation 1

Where:

  • ΔP.E = Change in the skier's potential energy
  • m = mass of the skier
  • Δh = change in height to which it was raised
  • g = acceleration due to gravity.

From the question,

Given:

  • m = 55 kg
  • Δh = 370 m
  • g = 9.8 m/s²

Substitute these values into equation 1

  • ΔP.E = 55×370×9.8
  • ΔP.E = 199430 J.

Hence, The change in the skier's gravitational potential energy is 199430 J.

Learn more about potential energy here: brainly.com/question/1242059

3 0
2 years ago
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