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Below is the answers:
Fullback running
<span>Mo = mass * velocity </span>
<span>Mo = 95kg * 8.2 m/s =779 kg*m/s (a </span>
<span>He got stopped Change in Mo = 779 kg*m/s (b </span>
<span>Both stopped ===> Tackle's mo = - Halfback's Mo = - 779 kg*m/s (c & d </span>
<span>- 779 = 128 * v </span>
<span>v= - 6.09 m/s (e</span>
Given:
density of air at inlet, 
density of air at inlet, 
Solution:
Now,

(1)
where
A = Area of cross section
= velocity of air at inlet
= velocity of air at outlet
Now, using eqn (1), we get:

= 1.14
% increase in velocity =
=114%
which is 14% more
Therefore % increase in velocity is 14%
Answer:

Explanation:
= Permittivity of free space = 
A = Area
h = Altitude = 600 m
Electric flux through the top would be
(negative as the electric field is going into the volume)
At the bottom

Total flux through the volume

Electric flux is given by

Charge per volume is given by

The volume charge density is 