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slamgirl [31]
3 years ago
6

The pressure on a 200 milliliter sample of CO2 (g) at constant temperature is increased from

Chemistry
1 answer:
balu736 [363]3 years ago
5 0

The answer for the following problem is mentioned below.

  • <u><em>Therefore the final volume of the gas is 100 ml.</em></u>

Explanation:

 Given:

Initial pressure (P_{1}) = 600 mm of Hg

Final pressure (P_{2}) = 1200 mm of Hg

Initial volume (V_{1}) = 200 ml      

To find:

Final volume (V_{2})

We know;

According to the ideal gas equation,

    P × V = n × R × T

Where;

P represents the pressure of the gas

V represents the volume of the gas

n represents the no of moles of the gas

R represents the universal gas constant

T represents the temperature of the gas

So,

 From the above mentioned equation,

        P × V = constant

\frac{P_{1} }{P_{2} } = \frac{V_{1} }{V_{2} }

Where,

(P_{1}) represents the initial pressure of the gas

(P_{2}) represents the final pressure of the gas

(V_{1})  represents the initial volume of the gas

(V_{2})  represents the final volume of the gas

So;

\frac{600}{1200} = \frac{V_{2} }{200}    

V_{2} = 100 ml

<u><em>Therefore the final volume of the gas is 100 ml.</em></u>                                                                                                                                                                              

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Se hace reaccionar 4,00 g de aluminio y 42,00 g de bromo, según la reacción: Al(s)+Br2(l)⟶AlBr3(s) Calcular las moles de AlBr3(s
NeX [460]

Answer:

0.145 moles de AlBr3.

Explanation:

¡Hola!

En este caso, al considerar la reacción química dada:

Al(s)+Br2(l)⟶AlBr3(s)

Es claro que primero debemos balancearla como se muestra a continuación:

2Al(s)+3Br2(l)⟶2AlBr3(s)

Así, calculamos las moles del producto AlBr3 por medio de las masas de ambos reactivos, con el fin de decidir el resultado correcto:

n_{AlBr_3}^{por\ Al}=4.00gAl*\frac{1molAl}{27gAl} *\frac{2molAlBr_3}{2molAl}=0.145mol AlBr_3\\\\n_{AlBr_3}^{por\ Br_2}=42.00gr*\frac{1molr}{160g Br_2} *\frac{2molAlBr_3}{3molBr_2}=0.175mol AlBr_3

Así, inferimos que el valor correcto es 0.145 moles de AlBr3, dado que viene del reactivo límite que es el aluminio.

¡Saludos!

3 0
2 years ago
An acid sample of an unknown concentration is contained in a erlenmeyer flask. Which technique below would be best suited to ana
Ivenika [448]

Answer:

Titration

Explanation:

The best technique which can be used to determine the number of moles of the HCl in the sample is titration.

The given amount of HCl solution must be titrated with known concentration of the base like NaOH.

The volume of NaOH required must be noted also.

According to the reaction,

NaOH+HCl\rightarrow NaCl+H_2O

At equivalence point

Moles of HCl = Moles of NaOH

Considering:-

Moles of HCl=Molarity_{NaOH}\times Volume_{NaOH}

Thus, in this way, moles of HCl can be determined.

4 0
2 years ago
The energy released per gram of material is __________.
OLga [1]

Answer:

I'm pretty sure the answer is C.

4 0
1 year ago
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scoray [572]
Use a calculator to add those thank you ur welcome
7 0
2 years ago
Na+ + Cl–  NaCl Which statement best describes the relationship between the substances in the equation?
ANTONII [103]

Answer : The number of sodium ions is equal to the number of formula units of salt.


Explanation : In the given reaction of NaCl the statement which describes it the best is that the number of sodium ions is found to be same along with the formula units in the product side.


Na^{+} + Cl^{-} ----> NaCl.


Its clear from the equation that one mole of Na and one mole of Cl combines together to give the product, which is one mole of NaCl. The number of ions on both the sides are equal.

3 0
3 years ago
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