The standard temperature and the pressure for a gas are 273 K and 1 atm (1.0 x 10⁵ Pa) respectively.
For this question, combined gas law can be added.
PV/T = K (constant)
for both situations that law can be added as;
P₁V₁/T₁ = P₂V₂/T₂
P₁ = 97 kPa P₂= 1.0 x 10⁵ Pa
T₁ = 303 K T₂ = 273 K
V₁ 140 mL V₂ = ?
V₂ = 122.3 mL
Hence, the volume of gas at STP = 122.3 mL
2AgNO3+K2CrO4⇒Ag2CrO4(s)+2KNO3
Hence by mixing 0.0024M AgNO3 and 0.004M
K2CrO4, we will have Ag2CrO4 which is precipitated out and leave us with
0.0024M KN03 which is mixed with (0.004-0.0024/2)M, it can be 0.0028M, of K2Cr04
Answer:
3,855.532 grams
Explanation:
1 pound = 453.592 grams
8.50 = ? grams
--> 8.50 * 453.592 = 3,855.532 grams.
Fe: 2 x 55.845 = 111.69
O: 3 x 15.9994= 47.9982
111.69 + 47.9982 = 159.69 g/mol