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3 years ago

What are the difference between a red giant and a red super giant

2 answers:

8 0

So, unlike red giants, red supergiants are simply bright, red stars. It so happens that they may be in the same evolutionary state, but it is also possible that they have moved on. For example, most massive stars will appear as red supergiants while helium is fused into carbon in the core.

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natka813 [3]3 years ago

5 0

Red giants are very large stars which are highly luminous and have an inflated outer surface with an approximate temperature of about 5000 degrees K or lower.

Whereas, Red supergiants are the largest stars in the whole universe in terms of volume but they are simply bright, red stars unlike the red giants.

Having said that, there are no agreed theoretical distinctions between the red giants and red supergiants so there is still a room for confusion to discriminate between the two.

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2. A 0.5 kg tennis ball has speed of 15m/s. what is the kinetic energy of tennis?

Talja [164]

Explanation:

Given

mass (m) = 0.5 kg

velocity (v) = 15 m/s

Now

Kinetic energy

= 1/2 *m*v²

= 1/2 * 0.5 * 12²

= 0.5 *0.5 * 144

= 36 joule

hope it will help

4 0

3 years ago

Butane, C4H10, is a component of natural gas that is used as fuel for cigarette lighters. The balanced equation of the complete

zavuch27 [327]

Answer:

So the volume will be 2.33 L

Explanation:

The reaction for the combustion is:

2 C₄H₁₀ (g) + 13 O₂ (g) → 8 CO₂ (g) + 10 H₂O (l)

mass of butane to moles (mass / molar mass)

1.4 g / 58 g/mol

= 0.024 moles

2 moles of butane can produce 8 moles of carbon dioxide

0.024 moles of butane must produce (0.024 × 8) /2

= 0.096 moles of CO₂

Now we apply the Ideal Gases Law to find out the volume formed.

P . V = n . R . T

p = 1atm

n = 0.096 mol

R = 0.082 L.atm/mol.K

T = 273 + 23 = 296K

V = ?

1atm × V = 0.096 mol × 0.082 L.atm/mol.K × 296K

V = 0.096 mol × 0.082 L.atm/mol.K × 296K / 1atm

= 2.33 L

So the volume will be 2.33 L

5 0

3 years ago

Read 2 more answers

Erbium (Er) is element 68 on the periodic table. A sample contains 5.04×1023 atoms of Er. Calculate the amount of Er.

Korvikt [17]

Answer:

139.98 g to nearest hundredth.

Explanation:

Using Avogadro's Number:

One mole (167.26 g) of Erbium equates to 6.022141 * 10^23 atoms.

So 5.04 * 10^23 = 167.26 * 5.04/6.022141

= 139,98 g.

3 0

3 years ago

Which of the following is a physical property of a substance?? A. Combustion B. Corrosion C. Tendency to tarnish D. Solubility

Fofino [41]

A physical property does not change the substance.

Solubility would be the answer since all of the rest are changing the substance. They all deal with bonds except solubility.

Answer: D. Solubility

6 0

3 years ago

Read 2 more answers

Gaseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 7.9 g of methane is

Vikki [24]

Explanation:

The given reaction is as follows.

$CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$

As it is known that number of moles equal mass divided by molar mass. Molar mass of methane is 16 g/mol.

Hence, No. of moles = $\frac{mass}{molar mass}$

= $\frac{7.9 g}{16 g/mol}$

= 0.493 mol

Molar mass of oxygen is 32 g/mol.

Hence, its number of moles = $\frac{mass}{molar mass}$

= $\frac{14.4 g}{32 g/mol}$

= 0.45 mol

As, it is shown from the reaction that 1 mole of methane needs 2 mole of oxygen.

Therefore, 0.493 mol of methane needs $2 \times 0.45 mol$ equals 0.9 moles of oxygen.

As there is only 0.45 moles of oxygen for the reaction. So, it means that oxygen is the limiting reagent.

Hence, for 0.45 moles of oxygen, methane required is as follows.

$\frac{0.45}{2}$ = 0.225 moles

So, 0.225 moles of methane is equal to $0.225 \times 16$ = 3.6 g

As, 3.6 g of methane reacts with oxygen. Therefore, amount of methane remains is calculated as follows.

(7.9 g - 3.6 g) = 4.3 g

Thus, we can conclude that the minimum mass of methane that could be left over by the chemical reaction is 4.3 g.

8 0

3 years ago