8.54. The last number is low so it can not round up to 5
Answer:
See below
Step-by-step explanation:
When we talk about the function
, the domain and codomain are generally defaulted to be subsets of the Real set. Once
and
such that
for
. Therefore,
![\[\sqrt{\cdot}: \mathbb R_{\geq 0} \to \mathbb R_{\geq 0} \]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7B%5Ccdot%7D%3A%20%5Cmathbb%20R_%7B%5Cgeq%200%7D%20%5Cto%20%5Cmathbb%20R_%7B%5Cgeq%200%7D%20%5C%5D)
![\[x \mapsto \sqrt{x}\]](https://tex.z-dn.net/?f=%5C%5Bx%20%5Cmapsto%20%5Csqrt%7Bx%7D%5C%5D)
But this table just shows the perfect square solutions.
Draw the shape by drawing dots at the co-ordinates.
Connect them in order, so if it's KLMN, connect K to L then to M then N.
Then, pick one of the points, I'd choose K, then move that dot 3 to the right, then move it 4 up. Do the same for all of the letters.