Answer:
The answer to your question is: more less
Explanation:
I suggest you these answers:
a) PCl₅ (s) ⇒ PCl₃ (s) + Cl₂ (g)
b) ZnBr₂ (aq) + Li₃CO₃ (aq) ⇒ ZnCO₃ (s) + LiBr (aq)
c) C₂H₄ + O₂ ⇒ CO₂ (g) + H₂O (l)
Do you have to balance them?
NaOH +HCl ---> NaCl +H2O
n (mol HCl) = n (mol NaOH)
M- molarity
V - volume
M(HCl)V(HCl) = M(NaOH)V(NaOH)
M(HCl)= M(NaOH)V(NaOH)/V(HCl)
M(HCl)= 10⁻³*25.3 ml/5.25 ml=<span>4.82 × 10⁻³ M molarity HCl</span>
<u>Answer:</u>
<u>For A:</u> The average molecular speed of Ne gas is 553 m/s at the same temperature.
<u>For B:</u> The rate of effusion of
gas is 
<u>Explanation:</u>
<u>For A:</u>
The average molecular speed of the gas is calculated by using the formula:

OR

where, M is the molar mass of gas
Forming an equation for the two gases:
.....(1)
Given values:

Plugging values in equation 1:

Hence, the average molecular speed of Ne gas is 553 m/s at the same temperature.
<u>For B:</u>
Graham's law states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass of the gas. The equation for this follows:

Where, M is the molar mass of the gas
Forming an equation for the two gases:
.....(2)
Given values:

Plugging values in equation 2:

Hence, the rate of effusion of
gas is 
Answer:
2.1 x 10^24
Explanation:
The number of atoms in a mole will always be the same. The fact that it's lithium is completely irrelevant.
One mole of anything is 6.022 x 10^23 atoms
So if we need to find the number of atoms in 3.5 mol we just need to multiply Avogadro's number by 3.5
3.5 x 6.022 x 10^23
= 21.077 x 10^23
To make it proper scientific notation the first number can't be greater than 10 so let's move the decimal place and increase the exponent
2.1077 x 10^24
Remove the numbers that aren't significant figures
2.1 x 10^24
Boom there's your answer