A zebra runs across a field at a constant speed of 14 m/s. The zebra would run 112 m in 8 seconds.
<u>Explanation: </u>
According to Kinematics, the distance travelled is given by the product of speed and time. Here, the speed given as 14 m/s, and time is 8 seconds. Now, the equation is as follows,
The required term to find as per the question is distance, so rearranging the above equation, we get,
By substituting the given values, we get, how much distance the zebra can run in time period of 8 seconds as,
Distance,
Answer:
Explanation:
Orbital velocity is the speed that a body that orbits around another body must have, for its orbit to be stable. For orbits with small eccentricity and when one of the masses is almost negligible compared to the other mass, like in this case, the orbital speed is given by:
Where M is the greater mass around which this negligible body is orbiting, r is the radius of the greater mass and G is the universal gravitational constant. So:
The Moon s escape speed will be smaller than Earth's.
The minimum speed that is required for an object to free itself from the gravitational force exerted by a massive object.
The formula of escape speed is
where
v is escape velocity
G is universal gravitational constant
M is mass of the body to be escaped from
r is distance from the center of the mass
we can say that,
Escape speed depends on the gravity of the object trying to hold the spacecraft from escaping.
we know that,
The Moon's surface gravity is about 1/6th as powerful or about 1.6 meters per second per second.
since, v ∝ g
The Moon s escape speed will be smaller than Earth's.
Learn more about escape speed here:
<u>brainly.com/question/15318861</u>
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