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Galina-37 [17]
3 years ago
9

A zebra runs across a field at a constant speed of 14m/s how far does the zebra go in 8 seconds?

Physics
2 answers:
Ratling [72]3 years ago
3 0

Answer:

112m/s

Explanation:

14x8=112 therefore meaning the zebra would run 112m/s

RoseWind [281]3 years ago
3 0

A zebra runs across a field at a constant speed of 14 m/s. The zebra would run 112 m in 8 seconds.

<u>Explanation: </u>

According to Kinematics, the distance travelled is given by the product of speed and time. Here, the speed given as 14 m/s, and time is 8 seconds. Now, the equation is as follows,

                     \text {velocity} = \frac{\text {distance}(s)}{\text {time}(t)}

The required term to find as per the question is distance, so rearranging the above equation, we get,

                     s = v e l o c i t y \times t

By substituting the given values, we get, how much distance the zebra can run in time period of 8 seconds as,

                     Distance, s = 14 \times 8 = 112 m

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(1) The wavelength of the wave is 1.164 m.

(2) The  velocity of the wave is 23.7 m/s.

(3) The maximum speed in the y-direction of any piece of the string is 6.14 m/s.

<h3> Wavelength of the wave</h3>

A general wave equation is given as;

y(x, t) = A sin(Kx - ωt)

<h3>Velocity of the wave</h3>

v = ω/K

From the given wave equation, we have,

y(x, t) = 0.048 sin(5.4x - 128t)

v = ω/K

where;

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  • k corresponds to 5.4

v = 128/5.4

v = 23.7 m/s

<h3>Wavelength of the wave</h3>

λ = 2π/K

λ = (2π)/(5.4)

λ = 1.164 m

<h3>Maximum speed of the wave</h3>

v(max) = Aω

where;

  • A is amplitude of the wave
  • ω is angular speed of the wave

v(max) = (0.048)(128)

v(max) = 6.14 m/s

Thus, the wavelength of the wave is 1.164 m.

The  velocity of the wave is 23.7 m/s.

The maximum speed in the y-direction of any piece of the string is 6.14 m/s.

Learn more about wavelength here: brainly.com/question/10728818

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3 0
2 years ago
IF YOU GOOD AT SCIENCE PLEASE ANSWER THIS ASAP
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I would believe that it would be the last option

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4 0
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Why do the waves have different speeds in different layers of Earth's surface?
Genrish500 [490]

Answer:

Material's density

Explanation:

Seismic waves travel at different rates of speed based on a material's density. Hopefully, you understand that the Earth has three main layers: the crust, mantle, and core. Earthquake waves move faster through solids.

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2 years ago
A piano tuner sounds two strings simultaneously. One has been previously tuned to vibrate at 293.0 Hz. The tuner hears 3.0 beats
ololo11 [35]

Answer:

Part a)

f_B = 290 Hz

Part B)

percentage increase is

percentage = 1.38%

Explanation:

Part a)

As we know that the beat frequency is

f_A - f_B = 3

after increasing the tension the beat frequency is decreased and hence the tension in string B will increase

So we have

293 - f_B = 3

f_B = 290 Hz

Part B)

percentage increase in the tension of the string will be given as

f_A - f_B' = 1

f_B' = 292 Hz

now we have

f = \frac{1}{2L}\sqrt{\frac{T}{\mu}}

so we have

T_1 = C (290)^2

T_2 = C(292)^2

so we have

\frac{\Delta T}{T} = \frac{292^2 - 290^2}{290^2}

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Where,

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Our values are given as

m_1 = 2190Kg

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m_2 = 3220kg

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Replacing we have that

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(2190)(10.5)+(3220)v_2 = (2190+3220)(4.74)

v_2 = 0.8224m/s

Therefore the the velocity of the 3220 kg car before the collision was 0.8224m/s

8 0
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