A zebra runs across a field at a constant speed of 14m/s how far does the zebra go in 8 seconds?

Physics

2 answers:

Ratling [72]3 years ago

3 0

Answer:

112m/s

Explanation:

14x8=112 therefore meaning the zebra would run 112m/s

RoseWind [281]3 years ago

3 0

A zebra runs across a field at a constant speed of 14 m/s. The zebra would run 112 m in 8 seconds.

Explanation: 

According to Kinematics, the distance travelled is given by the product of speed and time. Here, the speed given as 14 m/s, and time is 8 seconds. Now, the equation is as follows,

$\text {velocity} = \frac{\text {distance}(s)}{\text {time}(t)}$

The required term to find as per the question is distance, so rearranging the above equation, we get,

$s = v e l o c i t y \times t$

By substituting the given values, we get, how much distance the zebra can run in time period of 8 seconds as,

Distance, $s = 14 \times 8 = 112 m$

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A motorcycle is following a car that is traveling at a constant speed on a straight highway. Initially, the car and the motorcyc

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(a) 3.807 s

(b) 145.581 m

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Let Δt = t2 - t1 be the time it takes from the moment when the motorcycle starts to accelerate until it catches up with the car. We know that before the acceleration, both vehicles are travelling at a constant speed. So they would maintain a distance of 58 m prior to the acceleration.

The distance traveled by car after Δt (seconds) at $v_c = 23m/s$ speed is