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zalisa [80]
3 years ago
13

A 10-kilogram box is at static equilibrium, and the downward pull of gravity acting on the box is 98 newtons. What is the minimu

m force that would be required to just pick up the box?
Physics
2 answers:
polet [3.4K]3 years ago
5 0

Answer:

slightly greater than 98 newtons in the upward direction

Explanation:

this is a plato answer

Nikolay [14]3 years ago
4 0
The box is at equilibrium, so the net force on the box is zero (the force of gravity on the box is equal to the force exerted up on the box by the surface on which it rests.)
To pick up the box, our upward force must be greater than the force of gravity on the box (the weight). So, we must lift up the box with a force greater than 98 newtons. :)
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Answer:

Negative z-direction

Explanation:

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yawa3891 [41]

Answer:

L = 0 m

Therefore, the cricket was 0m off the ground when it became Moe’s lunch.

Explanation:

Let L represent Moe's height during the leap.

Moe's velocity v at any point in time during the leap is;

v = dL/dt = u - gt .......1

Where;

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The determine how far the cricket was off the ground when it became Moe’s lunch.

We need to integrate equation 1 with respect to t

L = ∫dL/dt = ∫( u - gt)

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Therefore, the cricket was 0m off the ground when it became Moe’s lunch.

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